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好的，所以我正在编写一个应用程序，它允许我从注册人的数据库中查看 Steam 数据。

我遇到了一个问题。首先，多用户的 Steam API 没有标准化。（例如，每次刷新时，用户的位置都会发生变化（这是什么API？！）

由于 steam 没有标准化 API，所以我必须自己做，所以在做了 json_decode($url, true) 之后。它不是一个关联数组。

我想按蒸汽 ID（数字）对 assoc 数组进行排序，并将它们与我自己的用户数据库（也包含蒸汽 ID，但可以在数据库中排序）进行匹配，那么我该怎么做呢？

例如

阵列 1：

array(3) {
  [0]=>
  array(2) {
    ["steam_id32"]=>
    string(17) "76561198025035234"
    ["name"]=>
    string(7) "Mitsuki"
  }
  [1]=>
  array(2) {
    ["steam_id32"]=>
    string(17) "76561197968270056"
    ["name"]=>
    string(3) "nrn"
  }
  [2]=>
  array(2) {
    ["steam_id32"]=>
    string(17) "76561197982490298"
    ["name"]=>
    string(4) "Ximp"
  }
}

阵列 2：

array(1) {
  ["response"]=>
  array(1) {
    ["players"]=>
    array(3) {
      [0]=>
      array(16) {
        ["steamid"]=>
        string(17) "76561197982490298"
        ["communityvisibilitystate"]=>
        int(3)
        ["profilestate"]=>
        int(1)
        ["personaname"]=>
        string(53) "……‮‮‮‮‮‮‮‮‮‮Ximp ……FUS RO DAH"
        ["lastlogoff"]=>
        int(1328569605)
        ["profileurl"]=>
        string(34) "http://steamcommunity.com/id/ximp/"
        ["avatar"]=>
        string(114) "http://media.steampowered.com/steamcommunity/public/images/avatars/f8/f8ee0cf00a2ec20417bf5b26b99fd6fb4dc176c1.jpg"
        ["avatarmedium"]=>
        string(121) "http://media.steampowered.com/steamcommunity/public/images/avatars/f8/f8ee0cf00a2ec20417bf5b26b99fd6fb4dc176c1_medium.jpg"
        ["avatarfull"]=>
        string(119) "http://media.steampowered.com/steamcommunity/public/images/avatars/f8/f8ee0cf00a2ec20417bf5b26b99fd6fb4dc176c1_full.jpg"
        ["personastate"]=>
        int(1)
        ["realname"]=>
        string(9) "I life in"
        ["primaryclanid"]=>
        string(18) "103582791430354400"
        ["timecreated"]=>
        int(1146939839)
        ["gameextrainfo"]=>
        string(20) "The Binding Of Isaac"
        ["gameid"]=>
        string(6) "113200"
        ["loccountrycode"]=>
        string(2) "DE"
      }
      [1]=>
      array(14) {
        ["steamid"]=>
        string(17) "76561197968270056"
        ["communityvisibilitystate"]=>
        int(3)
        ["profilestate"]=>
        int(1)
        ["personaname"]=>
        string(3) "nrn"
        ["lastlogoff"]=>
        int(1328618220)
        ["profileurl"]=>
        string(34) "http://steamcommunity.com/id/nrnx/"
        ["avatar"]=>
        string(114) "http://media.steampowered.com/steamcommunity/public/images/avatars/50/50b908e0aa2c730fa0f68ab0afc8b04fddb133f1.jpg"
        ["avatarmedium"]=>
        string(121) "http://media.steampowered.com/steamcommunity/public/images/avatars/50/50b908e0aa2c730fa0f68ab0afc8b04fddb133f1_medium.jpg"
        ["avatarfull"]=>
        string(119) "http://media.steampowered.com/steamcommunity/public/images/avatars/50/50b908e0aa2c730fa0f68ab0afc8b04fddb133f1_full.jpg"
        ["personastate"]=>
        int(1)
        ["realname"]=>
        string(9) "Nathaniel"
        ["primaryclanid"]=>
        string(18) "103582791432850562"
        ["timecreated"]=>
        int(1092771678)
        ["loccountrycode"]=>
        string(2) "US"
      }
      [2]=>
      array(14) {
        ["steamid"]=>
        string(17) "76561198025035234"
        ["communityvisibilitystate"]=>
        int(3)
        ["profilestate"]=>
        int(1)
        ["personaname"]=>
        string(23) "[ProudiA] Mitsuki Sakai"
        ["lastlogoff"]=>
        int(1328621807)
        ["commentpermission"]=>
        int(1)
        ["profileurl"]=>
        string(42) "http://steamcommunity.com/id/mitsukisakai/"
        ["avatar"]=>
        string(114) "http://media.steampowered.com/steamcommunity/public/images/avatars/9d/9d279f349422cbbed55adf1c8eabb0924ea0a719.jpg"
        ["avatarmedium"]=>
        string(121) "http://media.steampowered.com/steamcommunity/public/images/avatars/9d/9d279f349422cbbed55adf1c8eabb0924ea0a719_medium.jpg"
        ["avatarfull"]=>
        string(119) "http://media.steampowered.com/steamcommunity/public/images/avatars/9d/9d279f349422cbbed55adf1c8eabb0924ea0a719_full.jpg"
        ["personastate"]=>
        int(1)
        ["realname"]=>
        string(12) "酒井å‚è¼"
        ["primaryclanid"]=>
        string(18) "103582791432752089"
        ["timecreated"]=>
        int(1273714689)
      }
    }
  }
}
4

1 回答 1

-1

对于 sortig 数组，您可以在此处找到所需的所有函数的列表

更新：

首先，您必须1d从 a 创建一个数组，2d或者3d您可以使用此代码来制作一个易于访问的数组并且可排序（这是一个示例）：

<?php
$inArr;//This is the 2D array
$outArr = array();
for($i=0;$i<count($inArr);$i++){
   $outArr[$i] = $inArr[$i][0];
?>

然后你可以用ksort()or krsort()function.and 对它进行排序，将一个数组添加到另一个：

<?php
  $stack = array("value1", "value2");
  array_push($stack, "value3", "value4");
  print_r($stack);
?>
于 2012-02-07T17:41:45.433 回答