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我有以下类，它有很多私有变量。

class plantOfTheMonth {

//Declare which centre(s) are being used
private $centre = "";

//Declare the attributes of the current Plant Of The Month
private $name = "";
private $latinName = "";
private $image = "";
private $imageAlt = "";
private $imageLink = "";
private $strapLine = "";
private $description = "";
private $colour = "";
private $centres = "";

//Declare variables for error handling
private $issue = "";
private $issueCode = "";

public function __construct() {

}

public function returnAttributes() {

    $list = ""; //Set an Empty List

    foreach($this as $key => $value) {

        decodeText($value); //decode performs a stripslashes()
        $$key = $value; //Use a variable variable and assign a value to it 
        $list .= "'".$key."', "; //add it to the list for the compress()

    }

    $list .= substr($list, 0, -2); //Take the final ", " off
    return compact($list); //return the list of variables as an array

}
}

我想将所有属性作为带有它们的值的变量返回，以便我可以预先填写表单字段。我有一个填充所有属性的数据库查询（经测试证明有效）。在我之前 OO 的日子里，我从数据库中检索信息，将其放入变量中，然后使用 compress() 发送和 extract() 来获取所有变量。这是可行的吗，就像我课堂上的 returnAttributes() 方法一样？

4

1 回答 1

4

为什么搞得这么复杂？这是一个具有所需行为的代码少得多的示例。

public function returnAttributes()
{
    $list = array(); //Set an Empty List

    foreach(array_keys(get_class_vars(__CLASS__)) as $key)
    {
        $list[$key] = $this->$key;
    }

    return $list;
}
于 2012-02-07T17:16:35.820 回答