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我有一个包含许多头像和代理的游戏模型。当我删除游戏时,我想清理所有剩余的数据,所以我还想删除所有具有相应的头像和代理game_id

namespace app\models;

use app\models\Avatars;
use app\models\Agents;

class Games extends \lithium\data\Model
{
    public static function __init($options = array()) {
        parent::__init($options);
        $self = static::_instance(__CLASS__);

        Games::applyFilter('remove', function($self, $params, $chain) {

            $conditions = array( 'game_id' => $params['conditions']['_id'] );

            $message = new \app\extensions\helper\Message();
            $debugString = var_export($conditions, true);
            $message->addDebugMessage("params:{$debugString}");
            //Output: 
            //params:array ( 'game_id' => '4f301f69a170c8cf52000002', )


            if(!Agents::remove($conditions)) { $message->addErrorMessage('Es konnten nicht alle Agents geloescht werden.'); };
            if(!Avatars::remove($conditions)) { $message->addErrorMessage('Es konnten nicht alle Avatare geloescht werden.'); };

            return $chain->next($self, $params, $chain);
        });

    }
}

虽然游戏被删除,但代理和化身仍保留在 MongoDB 中。有人对此有提示吗?

db 中的代理示例

>db.agents.find()
{ "_id" : ObjectId("4f301f71a170c8391f000000"), "game_id" : ObjectId("4f301f69a170c8cf52000002"), "type" : "army", "subtype" : "deer", "units" : 5, "xPos" : 5, "yPos" : 5 }
4

1 回答 1

3

我必须看,但我不认为remove()铸造价值观。你需要这样做:

$conditions = array( 'game_id' => new MongoId($params['conditions']['_id']));
于 2012-02-07T13:42:25.923 回答