1

我正在从二进制文件中读取内容。如果我以 char 形式读入数据元素，我不会收到任何 malloc 错误，但如果我以任何其他数据类型（比如 short 或 int）形式读入，程序会成功读入字节，但是当我释放指针时，我会得到这可能是由于堆的损坏。有人可以告诉我我在做什么错吗？

编码：

#include <stdio.h>
#include <stdlib.h>

#define TYPE int //char or short

int main () {
  FILE * pFile;
  long lSize;
  TYPE * buffer;
  size_t result;

  pFile = fopen ( "4.bin" , "rb" );
  if (pFile==NULL) {fputs ("File error",stderr); exit (1);}

  // obtain file size:
  fseek (pFile , 0 , SEEK_END);
  lSize = ftell (pFile);
  rewind (pFile);

  // allocate memory to contain the whole file:
  buffer = (TYPE*) malloc (lSize/sizeof(TYPE));
  if (buffer == NULL) {fputs ("Memory error",stderr); exit (2);}

  // copy the file into the buffer:
  result = fread (buffer,sizeof(TYPE),lSize/sizeof(TYPE),pFile);
  if (result != lSize/sizeof(TYPE)) {fputs ("Reading error",stderr); exit (3);}
  perror("This is the problem: ");
  /* the whole file is now loaded in the memory buffer. */

  // terminate
  fclose (pFile);
  free (buffer);              // free causes heap related issue
  return 0;
}
4

1 回答 1

1

malloc以字节为单位的大小作为参数，因此该行

buffer = (TYPE*) malloc (lSize/sizeof(TYPE));

应该读

buffer = (TYPE*) malloc (lSize);
于 2012-02-05T03:08:20.560 回答