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请帮忙。我正在尝试使用我们产品拥有的当前资产数量来更新这张表。如果产品已经存在于表中，它应该更新产品的最新计数。但是，使用下面的查询，mysql 正在返回我

“错误 1111 (HY000)：无效使用组功能”。

我无法确定我的错误是什么，或者在“重复键”函数中使用计数是否真的有效：

INSERT INTO report_count_assets
    SELECT products.product_id, 
    count(product_assets.asset_id),
    count(case when assets.asset_type_id=1 THEN 1 END), 
    count(case when assets.asset_type_id=2 THEN 1 END), 
    count(case when assets.asset_type_id=3 THEN 1 END), 
    count(case when assets.asset_type_id=11 THEN 1 END) 
    FROM products 
    LEFT JOIN product_assets USING (product_id) 
    LEFT JOIN assets USING (asset_id)
    WHERE products.brand_id=671

ON DUPLICATE KEY UPDATE
    asset_count = count(product_assets.asset_id),
    asset_type_image = count(case when assets.asset_type_id=1 THEN 1 END), 
    asset_type_video = count(case when assets.asset_type_id=2 THEN 1 END), 
    asset_type_sound = count(case when assets.asset_type_id=3 THEN 1 END), 
    asset_type_install = count(case when assets.asset_type_id=11 THEN 1 END);
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2 回答 2

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我认为您不能在ON DUPLICATE. MySQL 看到你的 SQL 是这样的：

insert into report_count_assets
expr
on duplicate key update
...

ON DUPLICATE 不知道发生了什么expr，它只知道它有一个重复的行要处理。在不知道内部发生了什么的expr情况下，没有counts 可以操作的上下文。此外，您应该values在 UPDATE 中使用：

您可以使用子句中的VALUES(col_name)函数UPDATE来引用语句INSERT部分中的列值INSERT ... ON DUPLICATE KEY UPDATE。

并且values(count(x))不是有效的语法。但是values(column_name)是有效的，所以这应该有效：

INSERT INTO report_count_assets
(product_id, asset_count, asset_type_image, asset_type_video, asset_type_sound, asset_type_install)
    SELECT products.product_id, 
    count(product_assets.asset_id),
    count(case when assets.asset_type_id=1 THEN 1 END), 
    count(case when assets.asset_type_id=2 THEN 1 END), 
    count(case when assets.asset_type_id=3 THEN 1 END), 
    count(case when assets.asset_type_id=11 THEN 1 END) 
    FROM products 
    LEFT JOIN product_assets USING (product_id) 
    LEFT JOIN assets USING (asset_id)
    WHERE products.brand_id=671
ON DUPLICATE KEY UPDATE
    asset_count = values(asset_count),
    asset_type_image = values(asset_type_image), 
    asset_type_video = values(asset_type_video), 
    asset_type_sound = values(asset_type_sound), 
    asset_type_install = values(asset_type_install);

我不得不product_id猜测report_count_assets.

如果这不起作用（显然它不起作用），那么您可以通过预先计算 SELECT 来艰难地做到这一点。创建一个临时表：

create temporary table t (
    product_id int,
    product_count int,
    assets1 int,
    assets2 int,
    assets3 int,
    assets11 int
)

填充它：

INSERT INTO t (product_id, product_count, assets1, assets2, assets3, assets11)
SELECT products.product_id, 
count(product_assets.asset_id),
count(case when assets.asset_type_id=1 THEN 1 END), 
count(case when assets.asset_type_id=2 THEN 1 END), 
count(case when assets.asset_type_id=3 THEN 1 END), 
count(case when assets.asset_type_id=11 THEN 1 END) 
FROM products 
LEFT JOIN product_assets USING (product_id) 
LEFT JOIN assets USING (asset_id)
WHERE products.brand_id=671

然后使用该临时表执行您真正想做的插入：

insert into report_count_assets
    select product_id, product_count, assets1, assets2, assets3, assets11
    from t
on duplicate key update
    asset_count = values(product_count),
    asset_type_image = values(assets1),
    asset_type_video = values(assets2),
    asset_type_sound = values(assets3),
    asset_type_install = values(assets11)
于 2012-02-04T07:23:31.613 回答
0

尝试按 product_assets.asset_id 分组：

.
.
WHERE products.brand_id=671
group by product_assets.asset_id
ON DUPLICATE KEY UPDATE
    asset_count = count(product_assets.asset_id)
.
.
于 2012-02-04T07:27:03.317 回答