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我想删除 Word 文档的所有超链接并保留文本。我有这两种方法来阅读带有 doc 和 docx 扩展名的 word 文档。

private void readDocXExtensionDocument(){
    File inputFile = new File(inputFolderDir, "test.docx");
    try {
        XWPFDocument document = new XWPFDocument(OPCPackage.open(new   FileInputStream(inputFile)));
        XWPFWordExtractor extractor = new XWPFWordExtractor(document);
        extractor.setFetchHyperlinks(true);
        String context =  extractor.getText();
        System.out.println(context);
    } catch (InvalidFormatException e) {
        e.printStackTrace();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

}

private void readDocExtensionDocument(){
    File inputFile = new File(inputFolderDir, "test.doc");
    POIFSFileSystem fs;
    try {
        fs = new POIFSFileSystem(new FileInputStream(inputFile));
        HWPFDocument document = new HWPFDocument(fs);
        WordExtractor wordExtractor = new WordExtractor(document);
        String[] paragraphs = wordExtractor.getParagraphText();
        System.out.println("Word document has " + paragraphs.length + " paragraphs");
        for(int i=0; i<paragraphs.length; i++){
            paragraphs[i] = paragraphs[i].replaceAll("\\cM?\r?\n", "");
            System.out.println(paragraphs[i]);
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
}

是否可以使用 apache poi 库删除 word 文档的所有链接？如果不是，是否有任何其他库可以提供此功能？

4

1 回答 1

2

我的解决方案，至少对于 .docx 类别，是使用正则表达式。看看这个

private void readDocXExtensionDocument(){
   Pattern p = Pattern.compile("\\<(.+?)\\>");
   File inputFile = new File(inputFolderDir, "test.docx");
   try {
      XWPFDocument document = new XWPFDocument(OPCPackage.open(new   FileInputStream(inputFile)));
      XWPFWordExtractor extractor = new XWPFWordExtractor(document);
      extractor.setFetchHyperlinks(true);
      String context =  extractor.getText();
      Matcher m = p.matcher(context);
      while (m.find()) {
         String link = m.group(0); // the bracketed part
         String textString = m.group(1); // the text of the link without the brackets
         context = context.replaceAll(link, ""); // ordering important.  Link then textString
         context = context.replaceAll(textString, "");
      }
      System.out.println(context);
   } catch (InvalidFormatException e) {
    e.printStackTrace();
   } catch (FileNotFoundException e) {
    e.printStackTrace();
   } catch (IOException e) {
    e.printStackTrace();
   }
  }

这种方法的唯一警告是，如果这些尖括号的材料不是链接，也可以删除。如果您对可能出现的链接类型有更好的了解，您可以尝试使用更具体的正则表达式而不是我提供的正则表达式。

于 2012-10-12T16:07:02.707 回答