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我正在为我的公司制定一个软件的规范，作为审计系统的一部分，我认为如果有办法抓住当前的 Active Directory 用户，那就太好了。

希望是这样的：

Dim strUser as String
strUser = ActiveDirectory.User()
MsgBox "Welcome back, " & strUser
4

4 回答 4

6

试试这篇文章- 我有一些代码在工作中，如果这不可行的话......

相关报价：

Private Declare Function GetUserName Lib "advapi32.dll" Alias "GetUserNameA" _
                    (ByVal IpBuffer As String, nSize As Long) As Long
Private Declare Function GetComputerName Lib "kernel32" Alias "GetComputerNameA" _
                    (ByVal lpBuffer As String, nSize As Long) As Long

Function ThisUserName() As String
    Dim LngBufLen As Long
    Dim strUser As String

    strUser = String$(15, " ")
    LngBufLen = 15

    If GetUserName(strUser, LngBufLen) = 1 Then
        ThisUserName = Left(strUser, LngBufLen - 1)
    Else
        ThisUserName = "Unknown"
    End If
End Function

Function ThisComputerID() As String
    Dim LngBufLen As Long
    Dim strUser As String

    strUser = String$(15, " ")
    LngBufLen = 15

    If GetComputerName(strUser, LngBufLen) = 1 Then
        ThisComputerID = Left(strUser, LngBufLen)
    Else
        ThisComputerID = 0
    End If
End Function
于 2008-08-12T17:07:52.563 回答
4

这是我的版本：它将获取您喜欢的任何内容：

'gets firstname, lastname, fullname or username
Public Function GetUser(Optional whatpart = "username")
    Dim returnthis As String
    If whatpart = "username" Then GetUser = Environ("USERNAME"): Exit Function
    Set objSysInfo = CreateObject("ADSystemInfo")
    Set objUser = GetObject("LDAP://" & objSysInfo.USERNAME)
    Select Case whatpart
        Case "fullname": returnthis = objUser.FullName
        Case "firstname", "givenname": returnthis = objUser.givenName
        Case "lastname": returnthis = objUser.LastName
        Case Else: returnthis = Environ("USERNAME")
    End Select
    GetUser = returnthis
End Function

我从 Spiceworks 得到了最初的想法。

于 2015-07-18T22:14:47.730 回答
2

依赖环境变量保持有效是一个坏主意，因为它们很容易在用户会话中更改。

于 2008-09-15T22:17:06.850 回答
2

David 对使用环境变量的风险提出了很好的观点。我只能补充一点，环境变量可能还有其他问题。看看我们 5 年前的项目中的这个实际代码片段：

Public Function CurrentWorkbenchUser() As String

    ' 2004-01-05, YM: Using Application.CurrentUser for identification of 
    ' current user is very problematic (more specifically, extremely 
    ' cumbersome to set up and administer for all users). 
    ' Therefore, as a quick fix, let's use the OS-level user's 
    ' identity instead (NB: the environment variables used below must work fine
    ' on Windows NT/2000/2003 but may not work on Windows 98/ME)
    ' CurrentWorkbenchUser = Application.CurrentUser
    '
    ' 2005-06-13, YM: Environment variables do not work in Windows 2003. 
    ' Use Windows Scripting Host (WSH) Networking object instead.
    ' CurrentWorkbenchUser = Environ("UserDomain") & "\" & Environ("UserName")
    '
    ' 2007-01-23, YM: Somewhere between 2007-01-09 and 2007-01-20, 
    ' the WshNetwork object stopped working on CONTROLLER3. 
    ' We could not find any easy way to fix that.
    ' At the same time, it turns out that environment variables 
    ' do work on Windows 2003.
    ' (Apparently, it was some weird configuration problem back in 2005: 
    ' we had only one Windows 2003 computer at that time and it was 
    ' Will's workstation).
    '
    ' In any case, at the time of this writing, 
    ' returning to environment variables 
    ' appears to be the simplest solution to the problem on CONTROLLER3.
    ' Dim wshn As New WshNetwork
    ' CurrentWorkbenchUser = wshn.UserDomain & "\" & wshn.UserName

    CurrentWorkbenchUser = Environ("USERDOMAIN") & "\" & Environ("USERNAME")

End Function
于 2008-10-30T10:29:51.957 回答