我有这段代码使用标准套接字:
void set_fds(int sock1, int sock2, fd_set *fds) {
FD_ZERO (fds);
FD_SET (sock1, fds);
FD_SET (sock2, fds);
}
void do_proxy(int client, int conn, char *buffer) {
fd_set readfds;
int result, nfds = max(client, conn)+1;
set_fds(client, conn, &readfds);
while((result = select(nfds, &readfds, 0, 0, 0)) > 0) {
if (FD_ISSET (client, &readfds)) {
int recvd = recv(client, buffer, 256, 0);
if(recvd <= 0)
return;
send_sock(conn, buffer, recvd);
}
if (FD_ISSET (conn, &readfds)) {
int recvd = recv(conn, buffer, 256, 0);
if(recvd <= 0)
return;
send_sock(client, buffer, recvd);
}
set_fds(client, conn, &readfds);
}
我有套接字客户端和连接,我需要在它们之间“代理”流量(这是 socks5 服务器实现的一部分,您可能会看到https://github.com/mfontanini/Programs-Scripts/blob/master/socks5/socks5 .cpp)。我怎样才能在 asio 下实现这一点?
我必须指定在此之前两个套接字都在阻塞模式下运行。
尝试使用它但没有成功:
ProxySession::ProxySession(ba::io_service& ioService, socket_ptr socket, socket_ptr clientSock): ioService_(ioService), socket_(socket), clientSock_(clientSock)
{
}
void ProxySession::Start()
{
socket_->async_read_some(boost::asio::buffer(data_, 1),
boost::bind(&ProxySession::HandleProxyRead, this,
boost::asio::placeholders::error,
boost::asio::placeholders::bytes_transferred));
}
void ProxySession::HandleProxyRead(const boost::system::error_code& error,
size_t bytes_transferred)
{
if (!error)
{
boost::asio::async_write(*clientSock_,
boost::asio::buffer(data_, bytes_transferred),
boost::bind(&ProxySession::HandleProxyWrite, this,
boost::asio::placeholders::error));
}
else
{
delete this;
}
}
void ProxySession::HandleProxyWrite(const boost::system::error_code& error)
{
if (!error)
{
socket_->async_read_some(boost::asio::buffer(data_, max_length),
boost::bind(&ProxySession::HandleProxyRead, this,
boost::asio::placeholders::error,
boost::asio::placeholders::bytes_transferred));
}
else
{
delete this;
}
}
问题是,如果我这样做,ba::read(*socket_, ba::buffer(data_,256))
我可以通过 socks 代理读取来自浏览器客户端的数据,但在 ProxySession::Start 上面的版本中,在任何情况下都不会调用 HandleProxyRead。
我真的不需要在这里交换数据的异步方式,只是我在这里使用了这个解决方案。同样从我调用 ProxySession->start from code 开始,我需要引入睡眠,否则正在执行它的线程上下文将被关闭。
*更新 2 *请参阅下面我的更新之一。问题块变得太大了。