-1

我的 HTML 表单代码:

        <form action="upload.php" method="GET" enctyped="multipart/form-data">
            <label for="file"> Filename:</label>
            <input type="file" name="loadedFile" id="file"/></br>
            <input type="submit" name="uploadItNow" value="Submit"/>
            hai, this is this the uploader.
        </form>

PHP文件上传脚本:

if (isset($_GET['uploadItNow'])) // checks if submit button has pressed
{

    if ($_FILES['loadedFile']["error"] > 0)

        echo "Error: ". $_FILES["loadedFile"] ["error"]. "</br>";


    else
    {
        echo "Upload: ". $_FILES["loadedFile"] ["name"]. "</br>";
        echo "Type: ". $_FILES["loadedFile"] ["type"] . "</br>";
        echo "Stored in: " .$_FILES["loadedFile"] ["tmp_name"];
        echo "Size: ". ($_FILES["loadedFile"] ["size"] / 1024). " Kb</br>";

        //Copies file from TEMP_PHP dir to d.default dir
        if (file_exists("." . $_FILES["loadedFile"]["name"]))
        {
            echo $_FILES["loadedFile"]["name"] . " already exists. ";
        }

        else
        {
            move_uploaded_file($_FILES["loadedFile"]["tmp_name"],"." . $_FILES["loadedFile"]["name"]);
            echo "Stored in: " . "upload/" . $_FILES["loadedFile"]["name"];
        }
    }
} 

出于某种原因,它不起作用,我的脚本继续使用以下代码:

echo $_FILES["loadedFile"]["name"] . " already exists. ";
4

4 回答 4

4

您需要使用 POST 并将“enctyped”更改为“enctype”。

<form action="upload.php" method="POST" enctype="multipart/form-data">
于 2012-01-26T15:12:50.480 回答
3

尝试将表单方法更改为 POST

<form action="upload.php" method="POST" enctype="multipart/form-data">
于 2012-01-26T15:08:44.460 回答
1

尝试使用 POST 而不是 GET

也许该文件确实存在?而且你没有考虑路径

于 2012-01-26T15:09:44.193 回答
1

将方法更改为 post 并 enctyped 为 enctype

<form action="upload.php" method="POST" enctype="multipart/form-data">
于 2012-01-26T15:59:45.463 回答