我是 Python 和一般编程的完整初学者。我为Spotify 的 Best Before 拼图制作了一个程序。它被接受了。我在互联网上看了一点,并查看了该问题的其他解决方案,我见过的每个人都导入了几个模块,包括日历模块。我知道这可能是一个很好的解决方案,但我想自己做所有事情作为练习。
我真的很感激所有提示和提示,但主要是不必导入代码。主要是 theprinter(a)
和 detdataMaker()
需要修改。
normYear = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
leapYear = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
answerList = []
u''' Check if any of the integers are years '''
def yearCheck():
for x in xrange(0, 3):
a = dataList[x]
if len(a) > 2:
if not len(a) == 4 and int(a) in xrange(2000,3000):
if int(a) in xrange(100,1000):
dataList[x] = int(a) + 2000
else:
print data + u" is illegal"
u''' Make integers and sort '''
def integer():
for x in xrange(0, 3):
dataList[x] = int(dataList[x])
dataList.sort()
u''' Check for possible leap years '''
def leapYears():
global leapList
leapList = []
for x in xrange(0, 3):
if dataList[x] % 4 == 0:
if dataList[x] % 100 == 0:
if dataList[x] % 400 == 0:
leapList.append(x)
else:
leapList.append(x)
u''' Changes year type '''
def defYear(a):
global xYear
if a in leapList:
xYear = leapYear
else:
xYear = normYear
u''' Printer '''
def printer(a):
if dataList[a] < 2000:
dataList[a] += 2000
year = dataList[a]
del dataList[a]
if not dataList[0] == 0:
month = dataList.pop(0)
day = dataList.pop(0)
answerList.append(unicode(year))
answerList.append(unicode(u'%02d' % month))
answerList.append(unicode(u'%02d' % day))
print u'-'.join(answerList)
else:
print data + u" is illegal"
u''' Looks for legal dates, first [Y<M<D] then [M<Y<D] then [M,D,Y] '''
def dateMaker():
for x in xrange(0,4):
defYear(x)
if x == 0:
if dataList[1] <= 12 and dataList[2] <= xYear[dataList[1]-1]:
printer(x)
break
elif x == 1:
if dataList[0] <= 12 and dataList[2] <= xYear[dataList[0]-1]:
printer(x)
break
elif x == 2:
if dataList[0] <= 12 and dataList[1] <= xYear[dataList[0]-1]:
printer(x)
break
else:
print data + u" is illegal"
u''' Program '''
data = raw_input()
dataList = data.split(u"/")
yearCheck()
integer()
leapYears()
dateMaker()