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当我搜索15000 个结果时,有没有办法优化处理速度?

在我的视图中,我正在过滤搜索:

if form.is_valid():

      results = Screening.objects.filter(
         screening_date__range(form.cleaned_data['start_date'],form.cleaned_data['end_date']))

      if form.cleaned_data['company']:
          results = results.filter(company=form.cleaned_data['company'])
      if form.cleaned_data['company_job']:
          results = results.filter(company_job__in=form.cleaned_data['company_job'])
      if form.cleaned_data['company_job_type']:
          results = results.filter(company_job_type=form.cleaned_data['company_job_type'])
      if form.cleaned_data['reason']:
          results = results.filter(reason_for_testing__in=form.cleaned_data['reason'])`

在 TEMPLATE 中,传递的结果用作:

{% for result in results %}

      <td>{{ result.company.name}}</td>
      <td>{{ result.first_name }} {{ result.last_name }}</td>
      <td>{{ result.company_job.job_number }}</td>
      <td>{{ result.id }}</td>
      <td>{{ result.screening_date|date}}</td></tr>

有什么方法可以优化处理,还是在这种情况下我应该使用缓存或某事?

4

2 回答 2

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您绝对应该使用select_related来制作任何一个 DB 命中(而不是 N)。

然后分析代码,找到瓶颈并尝试优化它,而不是“一般优化”。

于 2012-01-24T11:38:45.243 回答
0

这不是答案,而只是让您的代码更易于阅读和使用的提示:

  filters = {
      'screening_date__range': (form.cleaned_data['start_date'],form.cleaned_data['end_date'])
  }

  if form.cleaned_data['company']:
      filters['company'] = form.cleaned_data['company']
  if form.cleaned_data['company_job']:
      filters['company_job__in'] = form.cleaned_data['company_job']
  if form.cleaned_data['company_job_type']:
      filters['company_job_type'] = form.cleaned_data['company_job_type']
  if form.cleaned_data['reason']:
      filters['reason_for_testing__in'] = form.cleaned_data['reason']

  Screening.objects.filter(**filters)
于 2012-01-24T16:09:15.863 回答