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假设在 node.js 上通过 nano 打开了一个 couchdb 会话

var dbserv = require('nano')('http://localhost:5984');

在 couchdb 服务器dbserv可以访问的地方,有一个用户数据库users,其中用户的字段groups是一个数组。

如果我想更新groups中的用户jimusers我将如何在不替换整个文档的情况下这样做?

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2 回答 2

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沙发数据库

要创建更新处理程序,请编写设计文档:

{
  "_id": "_design/yourapp",
  "updates": {
    "foo": "function(doc, req) {
      doc.groups.push(req.query.bar); // or do whatever you like with it
      return [doc, 'done'];
    }"
  }
}

并使用 id 将其放入您的数据库中_design/yourapp,然后像这样获取它:

http://localhost:5984/users/_design/yourapp/_update/foo/jim?bar=baz

纳米沙发

var dbserv = require('nano')('http://localhost:5984');
var db = dbserv.use('users');

var designdoc = {/* The above design document */};

db.insert(designdoc);

db.get('_design/yourapp/_update/foo/jim', {bar: 'baz'});

请注意,您只需要插入一次设计文档,您甚至可以手动使用curl,然后更新您的文档只需按照上述说明发出 GET 请求。

Disclaimer: untested and I never used nano before, but it should be on the lines of what you have to do.

于 2012-01-25T02:44:37.550 回答
4

Found a way to make updates, without all _design needs and such. The issue with Nano CouchDB is that the insert doesn't really provide a place to send the correct _rev that is needed for an update. Anyhow, there is a work around. What one needs to do, is to get the _rev value from the _id you want to update. So you use Nano db.get as the big function, get the _rev value and update your document. Here is a code sample:

 users.get('document_name', function(err, doc) {
        updaterev = doc._rev;
        users.insert({title:'here_ya_go',_rev:updaterev},'document_name', function(err, body , header) {
            if (!err)
            {
                console.log(body);
                res.send('update website succeed');
            }
            else
            {
                console.log(err.error);
            }
        });
  });

When the db.insert functions are inside db.get function, it gives us a chance to grab hold of the _rev and update out document.

I know, I probably didn't invent this, but it's important to have this piece of code to grab and go. Good luck.

于 2013-11-13T21:47:26.043 回答