Youtube API 以 RFC3339 格式返回日期字符串。我找到了如何手动解析它,无论如何,这太长了。
- (NSString *)userVisibleDateTimeStringForRFC3339DateTimeString:(NSString *)rfc3339DateTimeString
// Returns a user-visible date time string that corresponds to the
// specified RFC 3339 date time string. Note that this does not handle
// all possible RFC 3339 date time strings, just one of the most common
// styles.
{
NSString * userVisibleDateTimeString;
NSDateFormatter * rfc3339DateFormatter;
NSLocale * enUSPOSIXLocale;
NSDate * date;
NSDateFormatter * userVisibleDateFormatter;
userVisibleDateTimeString = nil;
// Convert the RFC 3339 date time string to an NSDate.
rfc3339DateFormatter = [[[NSDateFormatter alloc] init] autorelease];
enUSPOSIXLocale = [[[NSLocale alloc] initWithLocaleIdentifier:@"en_US_POSIX"] autorelease];
[rfc3339DateFormatter setLocale:enUSPOSIXLocale];
[rfc3339DateFormatter setDateFormat:@"yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'"];
[rfc3339DateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
date = [rfc3339DateFormatter dateFromString:rfc3339DateTimeString];
if (date != nil) {
// Convert the NSDate to a user-visible date string.
userVisibleDateFormatter = [[[NSDateFormatter alloc] init] autorelease];
assert(userVisibleDateFormatter != nil);
[userVisibleDateFormatter setDateStyle:NSDateFormatterShortStyle];
[userVisibleDateFormatter setTimeStyle:NSDateFormatterShortStyle];
userVisibleDateTimeString = [userVisibleDateFormatter stringFromDate:date];
}
return userVisibleDateTimeString;
}
我可以让一个函数包含这个,但我想知道 Cocoa 基础或标准 C 或 POSIX 库上是否有预定义的方式来执行此操作。如果有的话,我想使用它。你能告诉我有没有更简单的方法?或者,如果您确认这是最简单的方法,将不胜感激:)