我有以下 PHP 代码
$filename = 'a56.flv';
$file = "C:/xampp/htdocs/site/flv/a56.flv";
header("Content-Type: application/force-download");
header('Content-Type: video/x-flv');
header('Content-Disposition: attachment; filename="' . addslashes($filename) . '"');
//header("Content-Type: application/octet-stream");
header("Content-Type: application/download; charset=UTF-8");
header("Content-Description: File Transfer");
header("X-Sendfile: $file");
当我直接调用脚本(http://localhost/site/get2.php?ftype=flv&filename=a56.flv)时,它工作正常,但只要使用(http://localhost/site/vsrc_a56.flv)调用它返回 404 页面和这个 apache 错误:
[Sun Jan 15 02:01:44 2012] [error] [client 127.0.0.1] (20024)The given path is misformatted or contained invalid characters: xsendfile: unable to find file: flv/a56.flv
我的 .htaccess 文件如下所示:
IndexIgnore .htaccess */.??* *~ *# */HEADER* */README* */_vti*
AddDefaultCharset UTF-8
#########ErrorDocument 404
ErrorDocument 404 /site/404.php
RewriteEngine On
XSendFile on
RewriteRule ^vsrc_(.*)$ ./get2.php?ftype=flv&filename=$1 [L]