11

到目前为止，我有以下内容，但是如果没有一堆凌乱的 if 语句，我想不出一种整洁的方法来获取方向信。有任何想法吗？理想情况下，我想用一个类别来扩展 CLLocation 类来做到这一点。

-(NSString *)nicePosition{

double latitude = [self.latitude doubleValue];
double longitude = [self.longitude doubleValue];

int latSeconds = (int)round(latitude * 3600);
int latDegrees = latSeconds / 3600;
latSeconds = abs(latSeconds % 3600);
int latMinutes = latSeconds / 60;
latSeconds %= 60;

int longSeconds = (int)round(longitude * 3600);
int longDegrees = longSeconds / 3600;
longSeconds = abs(longSeconds % 3600);
int longMinutes = longSeconds / 60;
longSeconds %= 60;

//TODO: Use N,E,S,W notation in lat/long

return [NSString stringWithFormat:@"%i° %i' %i\", %i° %i' %i\"", latDegrees, latMinutes, latSeconds, longDegrees, longMinutes, longSeconds];
}

为了记录，我做了以下事情。

-(NSString *)nicePosition{

double latitude = [self.latitude doubleValue];
double longitude = [self.longitude doubleValue];

int latSeconds = (int)round(abs(latitude * 3600));
int latDegrees = latSeconds / 3600;
latSeconds = latSeconds % 3600;
int latMinutes = latSeconds / 60;
latSeconds %= 60;

int longSeconds = (int)round(abs(longitude * 3600));
int longDegrees = longSeconds / 3600;
longSeconds = longSeconds % 3600;
int longMinutes = longSeconds / 60;
longSeconds %= 60;

char latDirection = (latitude >= 0) ? 'N' : 'S';
char longDirection = (longitude >= 0) ? 'E' : 'W';

return [NSString stringWithFormat:@"%i° %i' %i\" %c, %i° %i' %i\" %c", latDegrees, latMinutes, latSeconds, latDirection, longDegrees, longMinutes, longSeconds, longDirection];
}
4

6 回答 6

15

标准方式：

char lonLetter = (lon > 0) ? 'E' : 'W';
char latLetter = (lat > 0) ? 'N' : 'S';
于 2012-01-13T14:14:13.430 回答
10

以下是基于 Daniel 上述解决方案的一些 Objective-C：

- (NSString*)coordinateString {

    int latSeconds = (int)(self.latitude * 3600);
    int latDegrees = latSeconds / 3600;
    latSeconds = ABS(latSeconds % 3600);
    int latMinutes = latSeconds / 60;
    latSeconds %= 60;

    int longSeconds = (int)(self.longitude * 3600);
    int longDegrees = longSeconds / 3600;
    longSeconds = ABS(longSeconds % 3600);
    int longMinutes = longSeconds / 60;
    longSeconds %= 60;

    NSString* result = [NSString stringWithFormat:@"%d°%d'%d\"%@ %d°%d'%d\"%@",
                        ABS(latDegrees),
                        latMinutes,
                        latSeconds,
                        latDegrees >= 0 ? @"N" : @"S",
                        ABS(longDegrees),
                        longMinutes,
                        longSeconds,
                        longDegrees >= 0 ? @"E" : @"W"];

    return result;    
}
于 2013-09-03T00:40:02.760 回答
3

这是 C# 中的一个解决方案：

    void Run(double latitude, double longitude)
    {
        int latSeconds = (int)Math.Round(latitude * 3600);
        int latDegrees = latSeconds / 3600;
        latSeconds = Math.Abs(latSeconds % 3600);
        int latMinutes = latSeconds / 60;
        latSeconds %= 60;

        int longSeconds = (int)Math.Round(longitude * 3600);
        int longDegrees = longSeconds / 3600;
        longSeconds = Math.Abs(longSeconds % 3600);
        int longMinutes = longSeconds / 60;
        longSeconds %= 60;

        Console.WriteLine("{0}° {1}' {2}\" {3}, {4}° {5}' {6}\" {7}",
            Math.Abs(latDegrees),
            latMinutes,
            latSeconds,
            latDegrees >= 0 ? "N" : "S",
            Math.Abs(longDegrees),
            longMinutes,
            longSeconds,
            latDegrees >= 0 ? "E" : "W");
    }

这是一个示例运行：

new Program().Run(-15.14131211, 56.345678);
new Program().Run(15.14131211, -56.345678);
new Program().Run(15.14131211, 56.345678);

哪个打印：

15° 8' 29" S, 56° 20' 44" W
15° 8' 29" N, 56° 20' 44" E
15° 8' 29" N, 56° 20' 44" E

希望这会有所帮助，并且它会做正确的事情。祝你好运！

于 2012-01-13T14:23:30.443 回答
3

如果你想快速做到这一点，你可以做这样的事情：

import MapKit

extension CLLocationCoordinate2D {

    var latitudeDegreeDescription: String {
        return fromDecToDeg(self.latitude) + " \(self.latitude >= 0 ? "N" : "S")"
    }
    var longitudeDegreeDescription: String {
        return fromDecToDeg(self.longitude) + " \(self.longitude >= 0 ? "E" : "W")"
    }
    private func fromDecToDeg(input: Double) -> String {
        var inputSeconds = Int(input * 3600)
        let inputDegrees = inputSeconds / 3600
        inputSeconds = abs(inputSeconds % 3600)
        let inputMinutes = inputSeconds / 60
        inputSeconds %= 60
        return "\(abs(inputDegrees))°\(inputMinutes)'\(inputSeconds)''"
    }
}
于 2016-06-21T14:42:05.197 回答
1

关于亚历克斯的回答，这是 Swift 3 中带有输出元组的解决方案。它返回元组中的坐标。

此外，它确实扩展了 CLLocationDegrees 类并且不需要额外的参数。

import MapKit

extension CLLocationDegrees {

    func degreeRepresentation() -> (northOrEast: Bool, degrees: Int, minutes: Int, seconds: Int) {
        var inputSeconds = Int(self * 3600)
        let inputDegrees = inputSeconds / 3600
        inputSeconds = abs(inputSeconds % 3600)
        let inputMinutes = inputSeconds / 60
        inputSeconds %= 60

        return (inputDegrees > 0, abs(inputDegrees), inputMinutes, inputSeconds)
    }

}
于 2017-06-02T13:59:21.803 回答
0 
int latSeconds = (int)round(abs(latitude * 3600));

这是错误！适当的是

int latSeconds = abs(round(latitude * 3600));
于 2013-04-16T17:22:19.663 回答