我找到了使用 java comm 发送短信的免费源项目: http ://code.google.com/p/find-ur-pal/source/browse/src/?r=21
发送短信的函数如下所示:
public void run(){
boolean timeOut=false;
long startTime=(new Date()).getTime();
while ((step <7) && (!timeOut)){
// log(""+((new Date()).getTime() - startTime);
//check where we are in specified delay
timeOut=((new Date()).getTime() - startTime)>delay;
//if atz does not work, type to send cntrlZ and retry, in case a message was stuck
if (timeOut && (step==1)) {
step=-1;
mySerial.send( ""+cntrlZ);
}
//read incoming string
String result= mySerial.getIncommingString() ;
// log ("<- "+result+"\n--------");
int expectedResult=-1;
try{
//log ("Step:"+step);
switch (step){
case 0:
mySerial.send("atz");
delay=LONG;
startTime=(new Date()).getTime();
break;
case 1:
delay=STANDARD;
mySerial.send("ath0");
startTime=(new Date()).getTime();
break;
case 2:
expectedResult=result.indexOf("OK");
//log ("received ok ="+expectedResult);
if (expectedResult>-1){
mySerial.send("at+cmgf=1");
startTime=(new Date()).getTime();
}else{
step=step-1;
}
break;
case 3:
expectedResult=result.indexOf("OK");
// log ("received ok ="+expectedResult);
if (expectedResult>-1){
mySerial.send("at+csca=\""+csca+"\"");
startTime=(new Date()).getTime();
}else{
step=step-1;
}
break;
case 4:
expectedResult=result.indexOf("OK");
// log ("received ok ="+expectedResult);
if (expectedResult>-1){
mySerial.send("at+cmgs=\""+recipient+"\"");
startTime=(new Date()).getTime();
}else{
step=step-1;
}
break;
case 5:
expectedResult=result.indexOf(">");
// log ("received ok ="+expectedResult);
if (expectedResult>-1){
mySerial.send(message+cntrlZ);
startTime=(new Date()).getTime();
}else{
step=step-1;
}
delay=VERYLONG;//waitning for message ack
break;
case 6:
expectedResult=result.indexOf("OK");
//read message number
if (expectedResult>-1){
int n=result.indexOf("CMGS:");
result=result.substring(n+5);
n=result.indexOf("\n");
status=0;
messageNo=Long.parseLong(result.substring(0,n).trim() );
log ("sent message no:"+messageNo);
}else{
step=step-1;
}
break;
}
step=step+1;
aThread.sleep(100);
}catch (Exception e){
e.printStackTrace();
}
}
mySerial.closeConnection() ;
//if timed out set status
if (timeOut ) {
status=-2;
log("*** time out at step "+step+"***");
}
}
AT 命令正在根据规范发送。它工作得很好,但现在我已经从收件箱中阅读了短信。我写过类似的函数:
public void receiveMessage() throws Exception
{
int expectedResult = 0;
SerialParameters params = defaultParameters;
mySerial =new SerialConnection (params);
mySerial.openConnection();
// step 1
mySerial.send("atz");
delay=LONG;
Thread.sleep(100);
//aThread.sleep(100);
String result= mySerial.getIncommingString() ;
// step 2
delay=STANDARD;
mySerial.send("ath0");
Thread.sleep(100);
// step 3
result= mySerial.getIncommingString() ;
expectedResult=result.indexOf("OK");
//log ("received ok ="+expectedResult);
if (expectedResult>-1){
mySerial.send("at+cmgf=1");
//startTime=(new Date()).getTime();
}
// step 4
result= mySerial.getIncommingString() ;
expectedResult=result.indexOf("OK");
//log ("received ok ="+expectedResult);
if (expectedResult>-1){
//mySerial.send("at+cmgl=\"ALL\"");
mySerial.send("at+cmgr=1");
//startTime=(new Date()).getTime();
}
Thread.sleep(100);
result= mySerial.getIncommingString() ;
}
在第 1 步中,我发送 atz 命令并得到响应 OK,然后是命令 ath0 和响应 OK,然后是命令 at+cmgl=\"ALL\" 并再次响应 OK,但是我的消息在哪里?我当时在想最后一个响应(getIncommingString)应该包含从收件箱中读取的消息。
我知道那是 SMSLib 和其他库。但是要使用这些库,我必须添加很多其他库(用于日志记录)。我想要一个简单的应用程序来发送和接收短信。
谢谢