我从 Maya 中启动 UI。如果 UI 尚未关闭,再次运行 UI 将完全冻结 Maya(出现错误“事件循环已在运行”)
在重新运行脚本之前手动关闭 UI 可以防止它冻结。但我想这并不实际。
有没有办法检测我尝试运行的 UI 是否已经存在?并可能强行关闭它?
我从 Maya 中启动 UI。如果 UI 尚未关闭,再次运行 UI 将完全冻结 Maya(出现错误“事件循环已在运行”)
在重新运行脚本之前手动关闭 UI 可以防止它冻结。但我想这并不实际。
有没有办法检测我尝试运行的 UI 是否已经存在?并可能强行关闭它?
这是一个使用QLockFile的非常简单的 PyQt5 解决方案:
from PyQt5 import QtCore, QtWidgets
lockfile = QtCore.QLockFile(QtCore.QDir.tempPath() + '/my_app_name.lock')
if lockfile.tryLock(100):
app = QtWidgets.QApplication([])
win = QtWidgets.QWidget()
win.setGeometry(50, 50, 100, 100)
win.show()
app.exec()
else:
print('app is already running')
Qt Wiki 上给出了一些相当简单的 C++ 解决方案,但这些解决方案似乎不再存在。我将其中一个移植到 PyQt,并在下面提供了一个示例脚本。最初的 C++ 解决方案已分为两类,因为可能不需要消息传递工具。
PyQt5:
from PyQt5 import QtWidgets, QtCore, QtNetwork
class SingleApplication(QtWidgets.QApplication):
messageAvailable = QtCore.pyqtSignal(object)
def __init__(self, argv, key):
super().__init__(argv)
# cleanup (only needed for unix)
QtCore.QSharedMemory(key).attach()
self._memory = QtCore.QSharedMemory(self)
self._memory.setKey(key)
if self._memory.attach():
self._running = True
else:
self._running = False
if not self._memory.create(1):
raise RuntimeError(self._memory.errorString())
def isRunning(self):
return self._running
class SingleApplicationWithMessaging(SingleApplication):
def __init__(self, argv, key):
super().__init__(argv, key)
self._key = key
self._timeout = 1000
self._server = QtNetwork.QLocalServer(self)
if not self.isRunning():
self._server.newConnection.connect(self.handleMessage)
self._server.listen(self._key)
def handleMessage(self):
socket = self._server.nextPendingConnection()
if socket.waitForReadyRead(self._timeout):
self.messageAvailable.emit(
socket.readAll().data().decode('utf-8'))
socket.disconnectFromServer()
else:
QtCore.qDebug(socket.errorString())
def sendMessage(self, message):
if self.isRunning():
socket = QtNetwork.QLocalSocket(self)
socket.connectToServer(self._key, QtCore.QIODevice.WriteOnly)
if not socket.waitForConnected(self._timeout):
print(socket.errorString())
return False
if not isinstance(message, bytes):
message = message.encode('utf-8')
socket.write(message)
if not socket.waitForBytesWritten(self._timeout):
print(socket.errorString())
return False
socket.disconnectFromServer()
return True
return False
class Window(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.edit = QtWidgets.QLineEdit(self)
self.edit.setMinimumWidth(300)
layout = QtWidgets.QVBoxLayout(self)
layout.addWidget(self.edit)
def handleMessage(self, message):
self.edit.setText(message)
if __name__ == '__main__':
import sys
key = 'app-name'
# send commandline args as message
if len(sys.argv) > 1:
app = SingleApplicationWithMessaging(sys.argv, key)
if app.isRunning():
print('app is already running')
app.sendMessage(' '.join(sys.argv[1:]))
sys.exit(1)
else:
app = SingleApplication(sys.argv, key)
if app.isRunning():
print('app is already running')
sys.exit(1)
window = Window()
app.messageAvailable.connect(window.handleMessage)
window.show()
sys.exit(app.exec_())
PyQt4:
# only needed for python2
import sip
sip.setapi('QString', 2)
from PyQt4 import QtGui, QtCore, QtNetwork
class SingleApplication(QtGui.QApplication):
messageAvailable = QtCore.pyqtSignal(object)
def __init__(self, argv, key):
QtGui.QApplication.__init__(self, argv)
# cleanup (only needed for unix)
QtCore.QSharedMemory(key).attach()
self._memory = QtCore.QSharedMemory(self)
self._memory.setKey(key)
if self._memory.attach():
self._running = True
else:
self._running = False
if not self._memory.create(1):
raise RuntimeError(self._memory.errorString())
def isRunning(self):
return self._running
class SingleApplicationWithMessaging(SingleApplication):
def __init__(self, argv, key):
SingleApplication.__init__(self, argv, key)
self._key = key
self._timeout = 1000
self._server = QtNetwork.QLocalServer(self)
if not self.isRunning():
self._server.newConnection.connect(self.handleMessage)
self._server.listen(self._key)
def handleMessage(self):
socket = self._server.nextPendingConnection()
if socket.waitForReadyRead(self._timeout):
self.messageAvailable.emit(
socket.readAll().data().decode('utf-8'))
socket.disconnectFromServer()
else:
QtCore.qDebug(socket.errorString())
def sendMessage(self, message):
if self.isRunning():
socket = QtNetwork.QLocalSocket(self)
socket.connectToServer(self._key, QtCore.QIODevice.WriteOnly)
if not socket.waitForConnected(self._timeout):
print(socket.errorString())
return False
if not isinstance(message, bytes):
message = message.encode('utf-8')
socket.write(message)
if not socket.waitForBytesWritten(self._timeout):
print(socket.errorString())
return False
socket.disconnectFromServer()
return True
return False
class Window(QtGui.QWidget):
def __init__(self):
QtGui.QWidget.__init__(self)
self.edit = QtGui.QLineEdit(self)
self.edit.setMinimumWidth(300)
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.edit)
def handleMessage(self, message):
self.edit.setText(message)
if __name__ == '__main__':
import sys
key = 'app-name'
# send commandline args as message
if len(sys.argv) > 1:
app = SingleApplicationWithMessaging(sys.argv, key)
if app.isRunning():
print('app is already running')
app.sendMessage(' '.join(sys.argv[1:]))
sys.exit(1)
else:
app = SingleApplication(sys.argv, key)
if app.isRunning():
print('app is already running')
sys.exit(1)
window = Window()
app.messageAvailable.connect(window.handleMessage)
window.show()
sys.exit(app.exec_())
如果有人想用 python3 运行@ekhumoro解决方案,则需要对字符串操作进行一些调整,我将在python 3工作的地方分享我的副本。
import sys
from PyQt4 import QtGui, QtCore, QtNetwork
class SingleApplication(QtGui.QApplication):
def __init__(self, argv, key):
QtGui.QApplication.__init__(self, argv)
self._memory = QtCore.QSharedMemory(self)
self._memory.setKey(key)
if self._memory.attach():
self._running = True
else:
self._running = False
if not self._memory.create(1):
raise RuntimeError( self._memory.errorString() )
def isRunning(self):
return self._running
class SingleApplicationWithMessaging(SingleApplication):
def __init__(self, argv, key):
SingleApplication.__init__(self, argv, key)
self._key = key
self._timeout = 1000
self._server = QtNetwork.QLocalServer(self)
if not self.isRunning():
self._server.newConnection.connect(self.handleMessage)
self._server.listen(self._key)
def handleMessage(self):
socket = self._server.nextPendingConnection()
if socket.waitForReadyRead(self._timeout):
self.emit(QtCore.SIGNAL('messageAvailable'), bytes(socket.readAll().data()).decode('utf-8') )
socket.disconnectFromServer()
else:
QtCore.qDebug(socket.errorString())
def sendMessage(self, message):
if self.isRunning():
socket = QtNetwork.QLocalSocket(self)
socket.connectToServer(self._key, QtCore.QIODevice.WriteOnly)
if not socket.waitForConnected(self._timeout):
print(socket.errorString())
return False
socket.write(str(message).encode('utf-8'))
if not socket.waitForBytesWritten(self._timeout):
print(socket.errorString())
return False
socket.disconnectFromServer()
return True
return False
class Window(QtGui.QWidget):
def __init__(self):
QtGui.QWidget.__init__(self)
self.edit = QtGui.QLineEdit(self)
self.edit.setMinimumWidth(300)
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.edit)
def handleMessage(self, message):
self.edit.setText(message)
if __name__ == '__main__':
key = 'foobar'
# if parameter no. 1 was set then we'll use messaging between app instances
if len(sys.argv) > 1:
app = SingleApplicationWithMessaging(sys.argv, key)
if app.isRunning():
msg = ''
# checking if custom message was passed as cli argument
if len(sys.argv) > 2:
msg = sys.argv[2]
else:
msg = 'APP ALREADY RUNNING'
app.sendMessage( msg )
print( "app is already running, sent following message: \n\"{0}\"".format( msg ) )
sys.exit(1)
else:
app = SingleApplication(sys.argv, key)
if app.isRunning():
print('app is already running, no message has been sent')
sys.exit(1)
window = Window()
app.connect(app, QtCore.SIGNAL('messageAvailable'), window.handleMessage)
window.show()
sys.exit(app.exec_())
示例 cli 调用,假设您的脚本名称是“SingleInstanceApp.py”:
python SingleInstanceApp.py 1
python SingleInstanceApp.py 1 "test"
python SingleInstanceApp.py 1 "foo bar baz"
python SingleInstanceApp.py 1 "utf8 test FOO ßÄÖÜ ßäöü łąćźżóń ŁĄĆŹŻÓŃ etc"
(这里是没有第一个参数的调用,所以消息根本不会被发送)
python SingleInstanceApp.py
希望它会帮助某人。
我的解决方案是这样的:
import sys
from PyQt5.QtCore import QLockFile
from PyQt5.QtWidgets import QApplication
from PyQt5.QtWidgets import QMessageBox
from window import MainWindow
if __name__ == "__main__":
try:
app_object = QApplication(sys.argv)
lock_file = QLockFile("app.lock")
if lock_file.tryLock():
window = MainWindow()
window.show()
app_object.exec()
else:
error_message = QMessageBox()
error_message.setIcon(QMessageBox.Warning)
error_message.setWindowTitle("Error")
error_message.setText("The application is already running!")
error_message.setStandardButtons(QMessageBox.Ok)
error_message.exec()
finally:
lock_file.unlock()