ruby-on-rails - 在嵌套资源路径中删除第二个模型名称

Question

我使用 slugs 作为 ID，所以想要 /songs/radiohead/karma-police 之类的 URL，而不是 /artists/radiohead/songs/karma-police。

蛞蝓可以通过以下方式实现：

def to_param
  slug
end

但是如何从标准 RESTful URL 中删除模型名称 - “歌曲”？

Answer 1

您可以通过将:path选项传递给您的resources调用来覆盖路径段。

resources :songs, path: "songs/:artist_id"

这将生成这些路线

      songs GET    /songs/:artist_id(.:format)          {:action=>"index", :controller=>"songs"}
            POST   /songs/:artist_id(.:format)          {:action=>"create", :controller=>"songs"}
   new_song GET    /songs/:artist_id/new(.:format)      {:action=>"new", :controller=>"songs"}
  edit_song GET    /songs/:artist_id/:id/edit(.:format) {:action=>"edit", :controller=>"songs"}
       song GET    /songs/:artist_id/:id(.:format)      {:action=>"show", :controller=>"songs"}
            PUT    /songs/:artist_id/:id(.:format)      {:action=>"update", :controller=>"songs"}
            DELETE /songs/:artist_id/:id(.:format)      {:action=>"destroy", :controller=>"songs"}

Answer 2

Put this in your routes.rb and it should work.

match 'artists/:artist_id/:id' => 'songs#show', :as => 'artist_song'

Make sure if you do the :as that the other routes don't take precedence over this one.

Then check out this Routing match reference