2

我有一个ListView显示 SQLite 表中的一组值。首先，我使用 aSimpleCursorAdapter来填充ListView基于 SQL 查询的游标。我改用 aSimpleAdapter是因为我必须在列表中操作/添加数据，然后才能将其发送到ListView.

使用敲击一行后SimpleCursorAdapter返回的idListView是数据库表中正确的id，但是使用SimpleAdapterid看起来就像它刚刚生成的一样，ListView因为它与位置相同。

我的表如下所示：

_id | col1 | col2 | col3

生成光标的方法SimpleCursorAdapter如下所示：

public Cursor fetchDataAsCursor()
{
  return db.query("table_name", new String[] { "_id", "col1", "col2"}, null, null, null, null, null);
}

填写ListViewusing的方法SimpleCursorAdapter如下所示：

  private void simpleFillData()
  {
    Cursor cursor = dbAdapter.fetchDataAsCursor();
    startManagingCursor(cursor);

    String[] from = new String[] {"col1", "col2"};
    int[] to = new int[] {R.id.col1, R.id.col2};

    SimpleCursorAdapter notes = new SimpleCursorAdapter(this,
        R.layout.list_row, cursor, from, to);
    setListAdapter(notes);
  }

这很好用，因为在以下方法中返回的 id 是可以的：

  protected void onListItemClick(ListView l, View v, int position, long id)
  {
    super.onListItemClick(l, v, position, id);
    Intent i = new Intent(this, DetailActivity.class);
    i.putExtra("_id", id);
    startActivityForResult(i, ACTIVITY_EDIT);
  }

现在切换到SimpleAdapter.

生成的代码List：

  public ArrayList<HashMap<String, Object>> getList()
  {
    ArrayList <HashMap<String, Object>> list = new ArrayList();

    c = fetchDataAsCursor();
    c.moveToFirst();
    for(int i = 0; i < c.getCount(); i++)
    {    
      HashMap<String, Object> h = new HashMap<String, Object>();
      h.put("_id", c.getLong(0));
      h.put("col1", c.getString(1));
      h.put("col2", c.getString(2));

      //This is the extra column
      h.put("extra", calculateSomeStuff(c.getString(1), c.getString(2));
      list.add(h);
      c.moveToNext();
    }

    return list;
  }

然后对于填充的方法ListView：

private void fillData()
  {
    ArrayList<HashMap<String, Object>> list = dbAdapter.getList();
    String[] from = new String[] {"col1", "col2", "extra"};
    int[] to = new int[] {R.id.col1, R.id.col2, R.id.extra};
    SimpleAdapter notes = new SimpleAdapter(this, list, R.layout.list_row, from, to);
    setListAdapter(notes);
  }

在最后一种方法中，ListView无法获取_id列表中的值。我猜想它会像使用SimpleCursorAdapter

有没有办法操纵 a 中行的 idListView以确保它与_id数据库表中的键具有相同的值？

（所有代码示例都大大简化了）

编辑：

我想到了。我必须创建自己的子类，SimpleAdapter其中覆盖public long getItemId(int position)

public class MyListAdapter extends SimpleAdapter
{
  private final String ID = "_id";
  public PunchListAdapter(Context context, List<? extends Map<String, ?>> data, int resource, String[] from, int[] to)
  {
    super(context, data, resource, from, to);
  }

  @Override
  public long getItemId(int position)
  {
    Object o = getItem(position);
    long id = position;
    if(o instanceof Map)
    {
      Map m = (Map)o;
      if(m.containsKey(ID))
      {
        o = m.get(ID);
        if(o instanceof Long)
          id = (Long)o;
      }
    } 
    return id;
  }
}
4

1 回答 1

0

这是使用 SimpleAdapter 处理光标的不好方法。您应该实现 CursorAdapter。

public class MyCursorAdapter extends CursorAdapter
{
      LayoutInflater inflater;
      public MyCursorAdapter(Context context, Cursor c) {
        super(context, c);
        inflater = LayoutInflater.from(context);
      }


 @Override
          public void bindView(View view, Context context, Cursor cursor) {
            //cursor is already setted to requared position, just get your column
            TextView tv1 = (TextView)view.findViewById(R.id.textView1);
            TextView tv2 = (TextView)view.findViewById(R.id.textView2);
            tv1.setText(cursor.getString(1));
            tv2.setText(cursor.getString(2));
            viev.addOnClickListener(new OnClickListener{
                 public void onClick(View v){
                    ...
                    cursor.getLong(0);
                    ...
                 }
            });       
          }


@Override
      public View newView(Context context, Cursor cursor, ViewGroup parent) {
        return inflater.inflate(R.layout.my_raw_view, parent, false);
      }
    }

不仅仅是在您的活动中将适配器设置为列表视图。

Cursor cursor = fetchDataAsCursor();
    ListView myListView = (ListView)findViewById(R.id.my_list_view);
    myListView.setAdapter(new MyCursorAdapter(this,cursot));
于 2013-02-22T15:40:05.417 回答