6

我的数据库正在变旧,而我最大的INT IDENTITY列之一的价值约为 13 亿。这将溢出大约 21 亿。我计划增加它的大小,但由于数据库中的记录数量,我不想太快这样做。我可能会在增加列大小之前更换我的数据库硬件,这可以抵消这可能导致的任何性能问题。我还想关注我的数据库中所有其他列已满 50% 的列。这是很多表,手动检查每一个是不切实际的。

这就是我现在获取值的方式(我知道返回的值可能有点过时,但对于我的目的来说已经足够了):

PRINT IDENT_CURRENT('MyDatabase.dbo.MyTable')

我可以使用INFORMATION_SCHEMA获取此信息吗?

4

4 回答 4

11

您可以查阅sys.identity_columns系统目录视图:

SELECT     
    name,
    seed_value, increment_value, last_value
FROM sys.identity_columns

这将为您提供每列的名称、种子、增量和最后一个值。该视图还包含数据类型,因此您可以很容易地找出哪些标识列可能很快就会用完数字......

于 2012-01-05T16:56:17.163 回答
5

我创建了一个存储过程来解决这个问题。它使用INFORMATION_SCHEMA来查找IDENTITY列,然后使用IDENT_CURRENT和列DATA_TYPE来计算已满百分比。将数据库指定为第一个参数,然后是可选的最小百分比和数据类型。

EXEC master.dbo.CheckIdentityColumns 'MyDatabase' --all

EXEC master.dbo.CheckIdentityColumns 'MyDatabase', 50 --columns 50% full or greater

EXEC master.dbo.CheckIdentityColumns 'MyDatabase', 50, 'int' --only int columns

示例输出:

Table                     Column             Type    Percent Full Remaining
------------------------- ------------------ ------- ------------ ---------------
MyDatabase.dbo.Table1     Table1ID           int     9            1,937,868,393
MyDatabase.dbo.Table2     Table2ID           int     5            2,019,944,894
MyDatabase.dbo.Table3     Table3ID           int     9            1,943,793,775

我创建了一个提醒,每月检查一次我的所有数据库,并将这些信息记录在电子表格中。

身份跟踪电子表格

CheckIdentityColumns 过程

USE master
GO

CREATE PROCEDURE dbo.CheckIdentityColumns
    (
    @Database       AS NVARCHAR(128),
    @PercentFull    AS TINYINT          = 0,
    @Type           AS VARCHAR(8)       = NULL
    )

AS

--this procedure assumes you are not using negative numbers in your identity columns

DECLARE @Sql NVARCHAR(3000)

SET @Sql = 
'USE ' + @Database + '

SELECT                        
    [Column].TABLE_CATALOG + ''.'' +
    [Column].TABLE_SCHEMA + ''.'' +
    [Table].TABLE_NAME          AS [Table],
    [Column].COLUMN_NAME                        AS [Column],
    [Column].DATA_TYPE              AS [Type],
    CAST((
    CASE LOWER([Column].DATA_TYPE)
    WHEN ''tinyint''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 255)  
    WHEN ''smallint''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 32767)  
    WHEN ''int''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 2147483647)  
    WHEN ''bigint''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 9223372036854775807)  
    WHEN ''decimal''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / (([Column].NUMERIC_PRECISION * 10) - 1))  
    END * 100) AS INT)                  AS [Percent Full],
    REPLACE(CONVERT(VARCHAR(19), CAST(
    CASE LOWER([Column].DATA_TYPE)
    WHEN ''tinyint''
    THEN (255 - IDENT_CURRENT([Table].TABLE_NAME))  
    WHEN ''smallint''
    THEN (32767 - IDENT_CURRENT([Table].TABLE_NAME))  
    WHEN ''int''
    THEN (2147483647 - IDENT_CURRENT([Table].TABLE_NAME))  
    WHEN ''bigint''
    THEN (9223372036854775807 - IDENT_CURRENT([Table].TABLE_NAME))  
    WHEN ''decimal''
    THEN ((([Column].NUMERIC_PRECISION * 10) - 1) - IDENT_CURRENT([Table].TABLE_NAME))  
    END
    AS MONEY) , 1), ''.00'', '''')              AS Remaining


FROM                       
    INFORMATION_SCHEMA.COLUMNS                  AS [Column]

    INNER JOIN    
    INFORMATION_SCHEMA.TABLES                   AS [Table]
    ON      [Table].TABLE_NAME                  = [Column].TABLE_NAME

WHERE
    COLUMNPROPERTY(
        OBJECT_ID([Column].TABLE_NAME), 
        [Column].COLUMN_NAME, ''IsIdentity'') = 1 --true
    AND [Table].TABLE_TYPE                      = ''Base Table'' 
    AND [Table].TABLE_NAME                      NOT LIKE ''dt%'' 
    AND [Table].TABLE_NAME                      NOT LIKE ''MS%'' 
    AND [Table].TABLE_NAME                      NOT LIKE ''syncobj_%''
    AND CAST(
    (
    CASE LOWER([Column].DATA_TYPE)
    WHEN ''tinyint''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 255)  
    WHEN ''smallint''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 32767)  
    WHEN ''int''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 2147483647)  
    WHEN ''bigint''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / 9223372036854775807)  
    WHEN ''decimal''
    THEN (IDENT_CURRENT([Table].TABLE_NAME) / (([Column].NUMERIC_PRECISION * 10) - 1))  
    END * 100
    ) AS INT)                                    >= ' + CAST(@PercentFull AS VARCHAR(4))

IF (@Type IS NOT NULL) 
    SET @Sql = @Sql + 'AND  LOWER([Column].DATA_TYPE)    = ''' + LOWER(@Type) + ''''

SET @Sql = @Sql + '

ORDER BY
    [Column].TABLE_CATALOG + ''.'' +
    [Column].TABLE_SCHEMA + ''.'' +
    [Table].TABLE_NAME,
    [Column].COLUMN_NAME'

EXECUTE sp_executesql @Sql
GO
于 2012-01-05T16:12:53.523 回答
2

Keith Walton 有一个非常全面的查询,非常好。这是一个更简单的方法,它基于标识列都是整数的假设:

SELECT sys.tables.name AS [Table Name], 
    last_value AS [Last Value],     
    MAX_LENGTH,
    CAST(cast(last_value as int) / 2147483647.0 * 100.0 AS DECIMAL(5,2)) 
        AS [Percentage of ID's Used], 
    2147483647 - cast(last_value as int) AS Remaining
FROM sys.identity_columns
    INNER JOIN sys.tables
        ON sys.identity_columns.object_id = sys.tables.object_id
ORDER BY last_value DESC

结果将如下所示:

Table Name      Last Value      MAX_LENGTH  Percentage of ID's Used   Remaining
My_Table        49181800             4               2.29             2098301847

检查整数标识列

于 2013-04-15T15:49:58.860 回答
1

在为这个问题制定解决方案时,我们发现这个线程既有信息又有趣(我们还写了一篇关于这个的详细帖子并描述了我们的工具是如何工作的)。

在我们的解决方案中,我们查询information_schema以获取所有列的列表。然后我们编写了一个程序,将遍历它们中的每一个并计算最大值和最小值(我们同时考虑上溢和下溢)。

SELECT
    b.COLUMN_NAME,
    b.COLUMN_TYPE,
    b.DATA_TYPE,
    b.signed,
    a.TABLE_NAME,
    a.TABLE_SCHEMA
FROM (
    -- get all tables
    SELECT
    TABLE_NAME, TABLE_SCHEMA
    FROM information_schema.tables
    WHERE 
    TABLE_TYPE IN ('BASE TABLE', 'VIEW') AND
    TABLE_SCHEMA NOT IN ('mysql', 'performance_schema')
) a
JOIN (
    -- get information about columns types
    SELECT
    TABLE_NAME,
    COLUMN_NAME,
    COLUMN_TYPE,
    TABLE_SCHEMA,
    DATA_TYPE,
    (!(LOWER(COLUMN_TYPE) REGEXP '.*unsigned.*')) AS signed
    FROM information_schema.columns
) b ON a.TABLE_NAME = b.TABLE_NAME AND a.TABLE_SCHEMA = b.TABLE_SCHEMA
ORDER BY a.TABLE_SCHEMA DESC;
于 2016-08-01T13:58:58.547 回答