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我正在尝试查询页面的所有相册并获取每个相册的封面照片。下面是我拥有的返回空结果的代码。

我可以分别进行这两个查询而不会出现问题，因此这不是权限问题。

$album_fql = "SELECT aid, owner, name, object_id, cover_pid, cover_object_id 
              FROM album
              WHERE owner = 'xxxxxxx'";

$albumpic_fql = "SELECT pid, src_small
                 FROM photo 
                 WHERE pid IN (SELECT cover_pid FROM #query1)";

$album_param = array(
                 'method'    => 'fql.multiquery',
                 'queries'   => '{"query1":"' . $album_fql . '", "query2":"' . $albumpic_fql . '"}');

$album_fqlResult = $facebook->api($album_param);

print_r($album_fqlResult);

有任何想法吗？

4

2 回答 2

1

您可以在嵌套查询中执行此操作，而不是作为多查询。

SELECT pid, src_small 
FROM photo 
WHERE pid in (SELECT cover_pid FROM album where owner={page id here})

例如，这是我从可口可乐的 Facebook 页面获得的专辑封面列表

SELECT pid, src_small 
FROM photo 
WHERE pid in (SELECT cover_pid FROM album where owner=40796308305)
LIMIT 5

回来：

{
  "data": [
    {
      "pid": "40796308305_2143765",
      "object_id": 110516463305,
      "src_small": "https://fbcdn-photos-a.akamaihd.net/hphotos-ak-snc1/6570_110516463305_40796308305_2143765_6253354_t.jpg"
    },
    {
      "pid": "40796308305_8753877",
      "object_id": "10150500888203306",
      "src_small": "https://fbcdn-photos-a.akamaihd.net/hphotos-ak-ash4/398389_10150500888203306_40796308305_8753877_1814220329_t.jpg"
    },
    {
      "pid": "40796308305_8751674",
      "object_id": "10150500434253306",
      "src_small": "https://fbcdn-photos-a.akamaihd.net/hphotos-ak-ash4/407475_10150500434253306_40796308305_8751674_1040781388_t.jpg"
    },
    {
      "pid": "40796308305_8742570",
      "object_id": "10150498588158306",
      "src_small": "https://fbcdn-photos-a.akamaihd.net/hphotos-ak-ash4/396541_10150498588158306_40796308305_8742570_1378170213_t.jpg"
    },
    {
      "pid": "40796308305_8742259",
      "object_id": "10150498546173306",
      "src_small": "https://fbcdn-photos-a.akamaihd.net/hphotos-ak-snc7/402667_10150498546173306_40796308305_8742259_287537096_t.jpg"
    }
  ]
}

如果你想尝试你的多重查询，然后尝试从索引 0 而不是 1 开始命名查询。例如 query0 和 query1 这是 C# SDK 允许它的唯一方式，也许 php SDK 也需要它。

于 2011-12-29T21:25:32.023 回答
1

终于想通了。我不得不将查询合并到 1 个变量中并转义单引号。

    $queries = '{

"query1" : "SELECT aid, name, cover_pid FROM album WHERE owner = \'xxxxxxxxxxx\'",

"query2" : "SELECT aid, images FROM photo WHERE pid IN (SELECT cover_pid FROM #query1)"

}';
于 2011-12-30T16:09:25.083 回答