python - 如何构建多个提交按钮 django 表单？

Question

我有一个表单输入电子邮件和两个提交按钮来订阅和取消订阅时事通讯：

<form action="" method="post">
{{ form_newsletter }}
<input type="submit" name="newsletter_sub" value="Subscribe" />
<input type="submit" name="newsletter_unsub" value="Unsubscribe" />
</form>

我也有班级形式：

class NewsletterForm(forms.ModelForm):
    class Meta:
        model = Newsletter
        fields = ('email',)

我必须编写自己的 clean_email 方法，并且我需要知道表单是通过哪个按钮提交的。但是提交按钮的值不在self.cleaned_data字典中。否则我可以得到按钮的值吗？

score 263 · Accepted Answer

例如：

if 'newsletter_sub' in request.POST:
    # do subscribe
elif 'newsletter_unsub' in request.POST:
    # do unsubscribe

score 114 · Accepted Answer

您可以在验证前使用self.datainclean_email方法访问 POST 数据。它应该包含一个名为newsletter_sub或newsletter_unsub取决于按下哪个按钮的键。

# in the context of a django.forms form

def clean(self):
    if 'newsletter_sub' in self.data:
        # do subscribe
    elif 'newsletter_unsub' in self.data:
        # do unsubscribe

score 36 · Accepted Answer

你也可以这样做，

 <form method='POST'>
    {{form1.as_p}}
    <button type="submit" name="btnform1">Save Changes</button>
    </form>
    <form method='POST'>
    {{form2.as_p}}
    <button type="submit" name="btnform2">Save Changes</button>
    </form>

代码

if request.method=='POST' and 'btnform1' in request.POST:
    do something...
if request.method=='POST' and 'btnform2' in request.POST:
    do something...

score 7 · Accepted Answer

同一个视图的一个网址！像这样！

网址.py

url(r'^$', views.landing.as_view(), name = 'landing'),

视图.py

class landing(View):
        template_name = '/home.html'
        form_class1 = forms.pynamehere1
        form_class2 = forms.pynamehere2
            def get(self, request):
                form1 = self.form_class1(None)
                form2 = self.form_class2(None)
                return render(request, self.template_name, { 'register':form1, 'login':form2,})

             def post(self, request):
                 if request.method=='POST' and 'htmlsubmitbutton1' in request.POST:
                        ## do what ever you want to do for first function ####
                 if request.method=='POST' and 'htmlsubmitbutton2' in request.POST:
                         ## do what ever you want to do for second function ####
                        ## return def post###  
                 return render(request, self.template_name, {'form':form,})

/home.html
    <!-- #### form 1 #### -->
    <form action="" method="POST" >
      {% csrf_token %}
      {{ register.as_p }}
    <button type="submit" name="htmlsubmitbutton1">Login</button>
    </form>
    <!--#### form 2 #### -->
    <form action="" method="POST" >
      {% csrf_token %}
      {{ login.as_p }}
    <button type="submit" name="htmlsubmitbutton2">Login</button>
    </form>

score 5 · Accepted Answer

现在这是一个老问题，但我遇到了同样的问题并找到了一个适合我的解决方案：我写了 MultiRedirectMixin。

from django.http import HttpResponseRedirect

class MultiRedirectMixin(object):
    """
    A mixin that supports submit-specific success redirection.
     Either specify one success_url, or provide dict with names of 
     submit actions given in template as keys
     Example: 
       In template:
         <input type="submit" name="create_new" value="Create"/>
         <input type="submit" name="delete" value="Delete"/>
       View:
         MyMultiSubmitView(MultiRedirectMixin, forms.FormView):
             success_urls = {"create_new": reverse_lazy('create'),
                               "delete": reverse_lazy('delete')}
    """
    success_urls = {}  

    def form_valid(self, form):
        """ Form is valid: Pick the url and redirect.
        """

        for name in self.success_urls:
            if name in form.data:
                self.success_url = self.success_urls[name]
                break

        return HttpResponseRedirect(self.get_success_url())

    def get_success_url(self):
        """
        Returns the supplied success URL.
        """
        if self.success_url:
            # Forcing possible reverse_lazy evaluation
            url = force_text(self.success_url)
        else:
            raise ImproperlyConfigured(
                _("No URL to redirect to. Provide a success_url."))
        return url

score 0 · Accepted Answer

我知道这是旧的，但至少可以说，有些答案很简短，而且它们没有解决表单不是 django 表单的常见情况。

这个解决方案的灵感来自这篇博文。它依赖于使用从 django.views.generic.edit.FormMixin 派生的视图类，例如 CreateView、UpdateView 或 DeleteView。这些提供了get_success_url方法，该方法在请求中公开按钮名称

html

<html>
    <body>
        <form method="post">
            <div>
                <label> <input type="radio" name="select-type" value="A">Type A</label>
            </div>
            <div>
                <label> <input type="radio" name="select-type" value="B">Type B</label>
            </div>
            <div>
                <input type="submit" value="Use selected">
            </div>
            <div>
                <input type="submit" name="no-selection" value="None of the above">
            </div>
        </form>
    </body>
</html>

视图.py

from django.views.generic import UpdateView

class GetType(UpdateView):
    def get(self, request):
        return render(request, 'get_type.html', {})

    def post(self, request):
        button = self.get_success_url()
        print(button)

    def get_success_url(self):
        if 'no-selection' in self.request.POST:
            return 'none selected'
        return ''

python - 如何构建多个提交按钮 django 表单？

6 回答 6

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