6

我正在处理这里的 pyes 用法示例

我正在用四个文档索引test-index并稍后使用不同的偏移量进行查询。start参数不会改变我的偏移量，无论它的值如何，我都会得到相同的结果。为什么会这样？

from pyes import *
conn = ES(["localhost:9200"])
try:
    conn.delete_index('test-index') 
except:
    pass

conn.create_index('test-index')

mapping = {u'name': {'boost': 1.0,
                 'index': 'analyzed',
                 'store': 'yes',
                 'type': u'string',
                 "term_vector" : "with_positions_offsets"},
       u'title': {'boost': 1.0,
                 'index': 'analyzed',
                 'store': 'yes',
                 'type': u'string',
                 "term_vector" : "with_positions_offsets"},
       u'pos': {'store': 'yes',
                 'type': u'integer'},
       u'uuid': {'boost': 1.0,
                'index': 'not_analyzed',
                'store': 'yes',
                'type': u'string'}}

conn.put_mapping("test-type", {'properties':mapping}, ["test-index"])

conn.index({"name":"Joe Tester", "uuid":"11111", "position":1}, "test-index", "test-type", 1)
conn.index({"name":"Bill Baloney", "uuid":"22222", "position":2}, "test-index", "test-type", 2)
conn.index({"name":"Joe Joseph", "uuid":"33333", "position":3}, "test-index", "test-type", 3)
conn.index({"name":"Last Joe", "uuid":"44444", "position":4}, "test-index", "test-type", 4)

conn.refresh(["test-index"])

q = TermQuery("name", "joe")
r0 = conn.search(q, indices = ["test-index"], start=0, size=1)
r1 = conn.search(q, indices = ["test-index"], start=1, size=1)
r2 = conn.search(q, indices = ["test-index"], start=2, size=1)

print('0: {0}'.format(r0['hits']['hits']))
print('1: {0}'.format(r1['hits']['hits']))
print('2: {0}'.format(r2['hits']['hits']))

输出：

$ python pagination.py 
0: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
1: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
2: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]

我的 pyes 版本是 0.16.0

4

2 回答 2

4

问题在于请求是如何发送到 ES 的，尽管我仍然不清楚它失败的原因。

而不是像我最初那样将查询直接发送到 ES：

r0 = conn.search(q, indexes = ["test-index"], start=0, size=1)
r1 = conn.search(q, indexes = ["test-index"], start=1, size=1)
r2 = conn.search(q, indexes = ["test-index"], start=2, size=1)

我将查询包装在 pyes.query.Search 对象中：

r0 = conn.search(Search(q, start=0, size=1), indexes = ["test-index"])
r1 = conn.search(Search(q, start=1, size=1), indexes = ["test-index"])
r2 = conn.search(Search(q, start=2, size=1), indexes = ["test-index"])

那行得通，请参阅下面的输出：

0s: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
1s: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'1', u'_source': {u'position': 1, u'name': u'Joe Tester', u'uuid': u'11111'}, u'_index': u'test-index'}]
2s: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'3', u'_source': {u'position': 3, u'name': u'Joe Joseph', u'uuid': u'33333'}, u'_index': u'test-index'}]
于 2011-12-29T18:24:59.347 回答
2

确保您使用Query 然后 Fetch的搜索类型。

于 2011-12-27T23:51:31.727 回答