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我正在尝试使用 WP7 应用程序中的 TweetSharp 和 Hammock 库将图片上传到 Twitpic。上传照片的代码是这样的:

// Clients.srv is a TweetSharp TwitterClient
RestRequest req = Clients.srv.PrepareEchoRequest();
RestClient client = new RestClient { Authority = "http://api.twitpic.com/", VersionPath = "2" };

req.AddFile("media", e.OriginalFileName, e.ChosenPhoto);
req.AddField("key", "hidden");
req.AddField("message", Tweet.Text);
req.Path = "upload.xml";
req.Method = Hammock.Web.WebMethod.Post; 

client.BeginRequest(req, (RestCallback) uploadCompleted);

对代码的一些解释:这来自对 photoPickerTask 的调用,e是包含照片名称和文件(一个 IO.Stream 对象)的事件参数。所有这些都被证实是有效的。

问题是 Twitpic 的响应始终是“无法验证您的身份:Twitter 拒绝了标头”。TwitterClient 工作正常,OAuth 令牌没问题。API 密钥是正确的。我不知道错误是来自我的代码、来自 TweetSharpPrepareEchoRequest()函数还是来自 Twitpic。任何人都可以给我一个线索吗?

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1 回答 1

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我今天遇到同样(和类似)的麻烦太多小时了。我终于通过将版本路径更改为 1 并将所有令牌输入到请求中来使其工作(如 twitpic doco 中所述)。我以为我昨天尝试了这个确切的组合,但它现在正在工作,所以手指交叉的 api 在此期间没有更新。

    TwitterService service = new TwitterService(consumerKey, consumerSecret);
    service.AuthenticateWith(accessToken, accessTokenSecret);

    if (thumbnail != null)  // an image post - go through twitpic
    {
        MemoryStream ms = new MemoryStream();
        thumbnail.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg);
        ms.Seek(0, SeekOrigin.Begin);

        // Prepare an OAuth Echo request to TwitPic
        RestRequest request = service.PrepareEchoRequest();
        request.Path = "uploadAndPost.xml";
        request.AddField("key", twitpicApiKey);
        request.AddField("consumer_token", consumerKey);
        request.AddField("consumer_secret", consumerSecret);
        request.AddField("oauth_token", accessToken);
        request.AddField("oauth_secret", accessTokenSecret);
        request.AddField("message", "Failwhale!");
        request.AddFile("media", "failwhale" + Environment.TickCount.ToString(), ms, "image/jpeg");

        // Post photo to TwitPic with Hammock
        RestClient client = new RestClient { Authority = "http://api.twitpic.com/", VersionPath = "1" };
        RestResponse response = client.Request(request);

        return response.Content;
    }
于 2011-12-28T08:35:01.170 回答