1

Sample of the code: 

    ServiceTemplate tmp1 = new ServiceTemplate(null, classes, null);

    try {

    /*      if(System.getSecurityManager() == null)

            System.setSecurityManager(new RMISecurityManager());*/

        thisIp = InetAddress.getLocalHost();
        LookupLocator locator = new LookupLocator("jini://"+thisIp.getHostName().toString());
        ServiceRegistrar sr = locator.getRegistrar();
        JavaSpace space = (JavaSpace)sr.lookup(tmp1);
        System.out.println("Success");

    }

Encountering error at [ ServiceRegistrar sr = locator.getRegistrar();] which states

java.net.ConnectException: Connection refused
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:182)
at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:366)
at java.net.Socket.connect(Socket.java:519)
at java.net.Socket.connect(Socket.java:469)
at java.net.Socket.<init>(Socket.java:366)
at java.net.Socket.<init>(Socket.java:209)
at net.jini.core.discovery.LookupLocator.getRegistrar(LookupLocator.java:328)
at net.jini.core.discovery.LookupLocator.getRegistrar(LookupLocator.java:286)
at MessageEntry.main(MessageEntry.java:34)

I am new to JavaSpace tech, kindly assist me.

Thank You in Advance

Jeetesh.N

4

1 回答 1

2

这ConnectException是一个非常基本的错误，它仅仅意味着您的 Java 进程无法建立到目标机器和端口的套接字连接，因为该机器不接受目标端口上的连接。在这种情况下，它几乎肯定会尝试localhost使用默认的 JINI 端口连接到您的 IP 地址。

我建议这个错误意味着您在执行代码时没有在您的机器上运行 JINI 服务/注册器。

于 2011-12-15T09:34:34.993 回答