4

我有一个函数,如果它存在则从表中获取 ID 并返回日期,如果不存在则返回当前日期:

CREATE FUNCTION [dbo].[CLOSEDATE] (@ID int)
RETURNS datetime
AS
  BEGIN
     DECLARE @closed int;
     DECLARE @result datetime;

     SELECT @result = created_on from dbo.statuses_history
            WHERE journalized_id = @ID and new_status = 'Закрыто';

     IF @result IS NULL    
        SELECT @result = GETDATE()     

     RETURN (DATEADD(dd, 0, DATEDIFF(dd, 0, @result)))
  END;

下一个查询从表中返回正确的日期:

select dbo.closedate(4170)
select dbo.closedate(id) from issues where id = 4170

下一个代码正确更新记录(表中的值):

DECLARE @d AS datetime
select @d = dbo.closedate(4170)
UPDATE issues SET created_on = @d  WHERE issues.id = 4170

但是如果我更新记录,我会在该字段中获得当前日期:

UPDATE issues
SET created_on = dbo.CloseDate(id)
WHERE issues.id = 4170

看起来 ID 参数没有传递给函数。

4

2 回答 2

2

您的测试(我在第一次阅读时错过了,抱歉)足以让我非常困惑。看来你的测试结果应该是不可能的。

我唯一的建议是重新编码函数,看看会发生什么......

CREATE FUNCTION [dbo].[CLOSEDATE] (@ID int)
RETURNS TABLE
AS
RETURN
  SELECT
    (DATEADD(dd, 0, DATEDIFF(dd, 0, ISNULL(MAX(created_on), GetDate())))) AS close_date
  FROM
    dbo.statuses_history
  WHERE
    journalized_id = @ID
    AND new_status = 'Закрыто'

进而...

UPDATE
  issues
SET
  created_on = fn.close_date
FROM
  issues
CROSS APPLY
  dbo.CLOSEDATE(id) AS fn
WHERE
  issues.id = 4170
于 2011-12-15T09:08:50.897 回答
0

我认为交叉应用是您要寻找的。

于 2011-12-15T08:36:55.387 回答