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我正在尝试整理一个 SQL 查询来收集过去一周内查看最多的 10 条新闻。我还需要它来过滤查看过相同新闻项目的重复 IP 地址。

每次用户进入页面时，都会获取用户的浏览器查询字符串。
这是数据库设置的示例：

datetime   | ipaddress     | querystring
-----------------------------------------
9/12/2011  | 65.65.65.651  | newsid=3512
9/12/2011  | 65.65.65.658  | newsid=3512
10/12/2011 | 65.65.65.653  | newsid=3514
11/12/2011 | 65.65.65.656  | newsid=3515
11/12/2011 | 65.65.65.651  | newsid=3515
13/12/2011 | 65.65.65.651  | newsid=3516
14/12/2011 | 65.65.65.650  | newsid=3516
14/12/2011 | 65.65.65.650  | newsid=3516

我失败的尝试：

 SELECT DISTINCT TOP 10 ipaddress, querystring, Count(*) AS thecount
      FROM [thedb].[dbo].[tblwebstats] 
      WHERE querystring LIKE '%newsid=%' AND datetime > (1 week ago)
      GROUP BY querystring, ipaddress
      ORDER BY Count(*) DESC

请帮帮我:)

4

3 回答 3

1

这样的事情怎么样？

select top 10 querystring, count(querystring) as popularity
from 
(
    select distinct ipaddress, querystring
    from 
    (
        select [datetime], ipaddress, querystring
        from tblwebstats
        where querystring LIKE '%newsid=%' AND [datetime] > dateadd(day, -7, getdate())
    ) as datefilter
) as distinctfilter
group by querystring
order by popularity desc

此查询执行以下操作（从最内到最外）：

  1. 根据需要按日期范围和查询字符串过滤原始表
  2. 将结果从 (1) 减少到不同的（IP 地址、查询字符串）对，忽略日期
  3. 计算来自 (2) 的唯一查询字符串出现次数，并按计数降序返回其中的前 10 个。
于 2011-12-14T00:46:38.130 回答
0

我假设当您说“......过滤重复的 IP 地址......”时，您只希望从同一个 IP 地址请求的同一篇新闻文章被计算一次（每天？）

如果是这样，您需要在获取文章之前过滤重复项，请尝试以下操作：

WITH Unique_Requests AS ( 
    SELECT DISTINCT datetime, ipaddress, querystring
    FROM [thedb].[dbo].[tblwebstats]
    WHERE datetime >= DATEADD(week, -1, CURRENT_TIMESTAMP) AND
        querystring LIKE '%newsid=%'
)

SELECT TOP 10 querystring, Count(*) AS thecount
FROM Unique_Requests
GROUP BY querystring
ORDER BY Count(*) DESC
于 2011-12-14T00:44:25.480 回答
0

对下面的陈述不是很满意。没有考虑到临时表的嵌套太多。如果您将数据放入额外的临时表中，则交叉应用将不那么繁重。

DECLARE @t as table(Created datetime,IPAddress varchar(15),QueryString VARCHAR(20))

INSERT INTO @t(Created,IPAddress,QueryString) VALUES
('2012-11-9' ,'65.65.65.651' ,'newsid=3512' ),
('2012-11-9','65.65.65.658','newsid=3512'),
('2012-11-10','65.65.65.653','newsid=3514'),
('2011-12-11','65.65.65.656','newsid=3515'),
('2011-12-11','65.65.65.651','newsid=3515'),
('2011-12-13','65.65.65.651','newsid=3516'),
('2011-12-14','65.65.65.650','newsid=3516'),
('2011-12-14','65.65.65.650','newsid=3516')

SELECT TOP 10 QueryString,DistinctIp,COUNT(1) Counter FROM (
SELECT DISTINCT Created,IPAddress,DistinctIp,QueryString
FROM @t t
CROSS APPLY (SELECT DISTINCT COUNT(1) DistinctIp FROM @t WHERE Created = t.Created ANd QueryString = t.QueryString) g
WHERE Created >= CAST((GETDATE()-7) AS DATE) AND
    QueryString LIKE '%newsid=%'
) x
GROUP BY QueryString,DistinctIp 
ORDER BY Counter DESC

语句的结果将包含不同 IP 地址的额外计数。

QueryString|DistinctIp|Counter
newsid=3515|2|2
newsid=3512|2|2
newsid=3516|2|1
newsid=3516|1|1
newsid=3514|1|1
于 2011-12-14T01:36:54.860 回答