如何组合两个返回验证的函数?以下是我没有奏效的尝试:
scala> def f: Int => Validation[String, Int] = i => if(i % 2 == 0) Success(i * 2) else Failure("Odd!")
f: Int => scalaz.Validation[String,Int]
scala> def g: Int => Validation[String, Int] = i => if(i > 0) Success(i + 1) else Failure("Not positive!")
g: Int => scalaz.Validation[String,Int]
scala> kleisli(f) >=> kleisli(g)
<console>:16: error: no type parameters for method kleisli: (f: A => M[B])scalaz.Kleisli[M,A,B] exist so that it can be applied to arguments (Int => scalaz.Validation[String,Int])
--- because ---
argument expression's type is not compatible with formal parameter type;
found : Int => scalaz.Validation[String,Int]
required: ?A => ?M[?B]
kleisli(f) >=> kleisli(g)
^
scala> type Va[+A] = Validation[String, A]
defined type alias Va
scala> kleisli[Va, Int, Int](f) >=> kleisli[Va, Int, Int](g)
<console>:17: error: could not find implicit value for parameter b: scalaz.Bind[Va]
kleisli[Va, Int, Int](f) >=> kleisli[Va, Int, Int](g)
^
这在 Haskell 中有效,所以我希望 Scalaz 也应该有一种方法。
λ> let f i = if i `mod` 2 == 0 then Right $ i * 2 else Left "Odd!"
λ> let g i = if i > 0 then Right $ i + 1 else Left "Not positive!"
λ> let h = f >=> g
λ> h 11
Left "Odd!"
λ> h (-4)
Left "Not positive!"
λ> h 4
Right 9