php - joomla 1.7 访问：受保护的菜单参数

Question

我想访问 joomla 1.7 中菜单的 menu_image 参数

Normally I just use:
$currentMenuItem = JSite::getMenu()->getActive();

它给了我下面的所有参数，但是 params 对象中的数据已经 :protected 所以我不能访问 $currentMenuItem->params->data:protected->menu_image 因为我不能在对象中使用 :。

Any1 知道该怎么做吗？

[params] => JRegistry Object
        (
            [data:protected] => stdClass Object
                (
                    [show_title] => 
                    [link_titles] => 
                    [show_intro] => 
                    [show_category] => 
                    [link_category] => 
                    [show_parent_category] => 
                    [link_parent_category] => 
                    [show_author] => 
                    [link_author] => 
                    [show_create_date] => 
                    [show_modify_date] => 
                    [show_publish_date] => 
                    [show_item_navigation] => 
                    [show_vote] => 
                    [show_icons] => 
                    [show_print_icon] => 
                    [show_email_icon] => 
                    [show_hits] => 
                    [show_noauth] => 
                    [menu-anchor_title] => 
                    [menu-anchor_css] => 
                    [menu_image] => images/joomla_black.gif
                    [menu_text] => 1
                    [page_title] => 
                    [show_page_heading] => 0
                    [page_heading] => 
                    [pageclass_sfx] => 
                    [menu-meta_description] => 
                    [menu-meta_keywords] => 
                    [robots] => 
                    [secure] => 0
                )

        )

Answer 1

正如@tereško 指出的那样：您扩展了类并创建了一个 getter 。好吧，obv joomla 已经有了一个吸气剂：所以就这样（例如，获取受保护的 menu_image）

$currentMenuItem = JSite::getMenu()->getActive();
$currentMenuItem->params->get('menu_image', 'images/no-image.jpg');