19

我正在寻找一个 t-sql 脚本，它可以列出数据库以及为特定用户映射的相应角色/权限。使用 SQL Server 2008 R2。

4

7 回答 7

38 
CREATE TABLE #tempww (
    LoginName nvarchar(max),
    DBname nvarchar(max),
    Username nvarchar(max), 
    AliasName nvarchar(max)
)

INSERT INTO #tempww 
EXEC master..sp_msloginmappings 

-- display results
SELECT * 
FROM   #tempww 
ORDER BY dbname, username

-- cleanup
DROP TABLE #tempww
于 2012-02-20T05:48:22.897 回答
4 
CREATE TABLE #tempww (

    LoginName nvarchar(max),
    DBname nvarchar(max),
    Username nvarchar(max), 
    AliasName nvarchar(max)
)

INSERT INTO #tempww 

EXEC master..sp_msloginmappings 

-- display results

declare @col varchar(1000)

declare @sql varchar(2000)

select @col = COALESCE(@col + ', ','') + QUOTENAME(DBname)

from #tempww Group by DBname

Set @sql='select * from (select LoginName,Username,AliasName,DBname,row_number() over(order by (select 0)) rn from #tempww) src

PIVOT (Max(rn) FOR DBname

IN ('+@col+')) pvt'

EXEC(@sql)



-- cleanup
DROP TABLE #tempww
于 2015-11-19T14:40:19.337 回答
2

我写了一个小查询来查找用户对特定数据库的权限。

    SELECT * FROM   
    (
    SELECT 
    perm.permission_name AS 'PERMISSION'
    ,perm.state_desc AS 'RIGHT'
    ,perm.class_desc AS 'RIGHT_ON'
    ,p.NAME AS 'GRANTEE'
    ,m.NAME AS 'USERNAME'
    ,s.name AS 'SCHEMA'
    ,o.name AS 'OBJECT'
    ,IIF(perm.class = 0, db_name(), NULL) AS 'DATABASE'
    FROM
    sys.database_permissions perm
    INNER JOIN sys.database_principals p ON p.principal_id = perm.grantee_principal_id
    LEFT JOIN sys.database_role_members rm ON rm.role_principal_id = p.principal_id
    LEFT JOIN sys.database_principals m ON rm.member_principal_id = m.principal_id
    LEFT JOIN sys.schemas s ON perm.class = 3 AND perm.major_id = s.schema_id
    LEFT JOIN sys.objects AS o ON perm.class = 1 AND perm.major_id = o.object_id
    UNION ALL
    SELECT 
    perm.permission_name AS 'PERMISSION'
    ,perm.state_desc AS 'RIGHT'
    ,perm.class_desc AS 'RIGHT_ON'
    ,'SELF-GRANTED' AS 'GRANTEE'
    ,p.NAME AS 'USERNAME'
    ,s.name AS 'SCHEMA'
    ,o.name AS 'OBJECT'
    ,IIF(perm.class = 0, db_name(), NULL) AS 'DATABASE'
    FROM
    sys.database_permissions perm
    INNER JOIN sys.database_principals p ON p.principal_id = perm.grantee_principal_id
    LEFT JOIN sys.schemas s ON perm.class = 3 AND perm.major_id = s.schema_id
    LEFT JOIN sys.objects AS o ON perm.class = 1 AND perm.major_id = o.object_id
    ) AS [union]
    WHERE [union].USERNAME = 'Username' -- Username you will search for
    ORDER BY [union].RIGHT_ON, [union].PERMISSION, [union].GRANTEE

固定数据库角色的权限不会出现在 sys.database_permissions 中。因此，数据库主体可能具有此处未列出的其他权限。

我不喜欢

    EXECUTE AS USER = 'userName';
    SELECT * FROM fn_my_permissions(NULL, 'DATABASE')

因为它只是检索用户没有来自哪里的权限！

也许我有一天会发现如何加入为用户授予的固定数据库角色权限......

请享受生活并讨厌用户：D

于 2014-10-16T08:47:09.330 回答
1

从这里偷了这个。我发现它非常有用！

DECLARE @DB_USers TABLE
(DBName sysname, UserName sysname, LoginType sysname, AssociatedRole varchar(max),create_date datetime,modify_date datetime)

INSERT @DB_USers
EXEC sp_MSforeachdb

'
use [?]
SELECT ''?'' AS DB_Name,
case prin.name when ''dbo'' then prin.name + '' (''+ (select SUSER_SNAME(owner_sid) from master.sys.databases where name =''?'') + '')'' else prin.name end AS UserName,
prin.type_desc AS LoginType,
isnull(USER_NAME(mem.role_principal_id),'''') AS AssociatedRole ,create_date,modify_date
FROM sys.database_principals prin
LEFT OUTER JOIN sys.database_role_members mem ON prin.principal_id=mem.member_principal_id
WHERE prin.sid IS NOT NULL and prin.sid NOT IN (0x00) and
prin.is_fixed_role <> 1 AND prin.name NOT LIKE ''##%'''

SELECT

dbname,username ,logintype ,create_date ,modify_date ,

STUFF(

(

SELECT ',' + CONVERT(VARCHAR(500),associatedrole)

FROM @DB_USers user2

WHERE

user1.DBName=user2.DBName AND user1.UserName=user2.UserName

FOR XML PATH('')

)

,1,1,'') AS Permissions_user

FROM @DB_USers user1

GROUP BY

dbname,username ,logintype ,create_date ,modify_date

ORDER BY DBName,username
于 2013-09-24T18:29:36.583 回答
0

这是你想要的那种东西吗？您可能想要扩展它以从 sys 表中获取更多信息。

使用大师

DECLARE @name VARCHAR(50) -- 数据库名称

声明 db_cursor CURSOR FOR
从 sys.databases 中选择名称

打开 db_cursor  
FETCH NEXT FROM db_cursor INTO @name  

而@@FETCH_STATUS = 0  
开始  
       打印@name
      exec('USE ' + @name + '; select rp.name, mp.name from sys.database_role_members drm
            加入 sys.database_principals rp on (drm.role_principal_id = rp.principal_id)
            加入 sys.database_principal mp on (drm.member_principal_id = mp.principal_id)')
       FETCH NEXT FROM db_cursor INTO @name  
结尾  

关闭 db_cursor  
DEALLOCATE db_cursor
于 2011-12-12T07:46:20.963 回答
0

使用fn_my_permissions 

EXECUTE AS USER = 'userName';
SELECT * FROM fn_my_permissions(NULL, 'DATABASE')
于 2011-12-12T07:33:54.327 回答
0

你整理过这个吗？我刚刚在这里找到了这段代码：

http://www.pythian.com/news/29665/httpconsultingblogs-emc-comjamiethomsonarchive20070209sql-server-2005_3a00_-view-all-permissions-_2800_2_2900_-aspx/

我想我需要做一些调整，但基本上这已经为我整理好了！

我希望它也适合你！

Ĵ

于 2012-05-23T14:22:12.170 回答