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Objective-C 提供运行时反射特性。我正在尝试查找已声明属性的 getter/setter 选择器名称。我知道field/之类的基本规则setField:。无论如何,我认为运行时反射应该提供一个功能来解析完整抽象的名称,但我找不到该功能。

如何在Objective-C(实际上是Apple的Cocoa)中使用运行时反射解决声明属性的getter/setter方法选择器(不是实现)

或反向查询。(方法选择器→声明的属性)

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2 回答 2

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我认为只有使用显式声明属性(setter = XXX 和/或 getter = XXX)才能获取选择器名称

因此,要获取类“Cat”的某些属性“furType”的 getter 和 setter 选择器名称:

objc_property_t prop = class_getProperty([Cat class], "furType");

char *setterName = property_copyAttributeValue(prop, "S");
if (setterName == NULL) { /*Assume standard setter*/ }

char *getterName = property_copyAttributeValue(prop, "G");
if (getterName == NULL) { /*Assume standard getter */ }

除了遍历所有属性并查找匹配项之外,我不知道反向查询。希望有帮助。

于 2011-12-11T04:39:57.013 回答
2

我的 NSObject 类别的一点更新。希望这会对某人有所帮助:

+(SEL)getterForPropertyWithName:(NSString*)name {
    const char* propertyName = [name cStringUsingEncoding:NSASCIIStringEncoding];
    objc_property_t prop = class_getProperty(self, propertyName);

    const char *selectorName = property_copyAttributeValue(prop, "G");
    if (selectorName == NULL) {
        selectorName = [name cStringUsingEncoding:NSASCIIStringEncoding];
    }
    NSString* selectorString = [NSString stringWithCString:selectorName encoding:NSASCIIStringEncoding];
    return NSSelectorFromString(selectorString);
}

+(SEL)setterForPropertyWithName:(NSString*)name {
    const char* propertyName = [name cStringUsingEncoding:NSASCIIStringEncoding];
    objc_property_t prop = class_getProperty(self, propertyName);

    char *selectorName = property_copyAttributeValue(prop, "S");
    NSString* selectorString;
    if (selectorName == NULL) {
        char firstChar = (char)toupper(propertyName[0]);
        NSString* capitalLetter = [NSString stringWithFormat:@"%c", firstChar];
        NSString* reminder      = [NSString stringWithCString: propertyName+1
                                                     encoding: NSASCIIStringEncoding];
        selectorString = [@[@"set", capitalLetter, reminder, @":"] componentsJoinedByString:@""];
    } else {
        selectorString = [NSString stringWithCString:selectorName encoding:NSASCIIStringEncoding];
    }

    return NSSelectorFromString(selectorString);
}
于 2016-08-04T06:19:59.810 回答