我正在尝试在 java 中打开 MS Word 2003 文档，搜索指定的字符串并将其替换为新字符串。我使用 APACHE POI 来做到这一点。我的代码如下所示：
public void searchAndReplace(String inputFilename, String outputFilename,
HashMap<String, String> replacements) {
File outputFile = null;
File inputFile = null;
FileInputStream fileIStream = null;
FileOutputStream fileOStream = null;
BufferedInputStream bufIStream = null;
BufferedOutputStream bufOStream = null;
POIFSFileSystem fileSystem = null;
HWPFDocument document = null;
Range docRange = null;
Paragraph paragraph = null;
CharacterRun charRun = null;
Set<String> keySet = null;
Iterator<String> keySetIterator = null;
int numParagraphs = 0;
int numCharRuns = 0;
String text = null;
String key = null;
String value = null;
try {
// Create an instance of the POIFSFileSystem class and
// attach it to the Word document using an InputStream.
inputFile = new File(inputFilename);
fileIStream = new FileInputStream(inputFile);
bufIStream = new BufferedInputStream(fileIStream);
fileSystem = new POIFSFileSystem(bufIStream);
document = new HWPFDocument(fileSystem);
docRange = document.getRange();
numParagraphs = docRange.numParagraphs();
keySet = replacements.keySet();
for (int i = 0; i < numParagraphs; i++) {
paragraph = docRange.getParagraph(i);
text = paragraph.text();
numCharRuns = paragraph.numCharacterRuns();
for (int j = 0; j < numCharRuns; j++) {
charRun = paragraph.getCharacterRun(j);
text = charRun.text();
System.out.println("Character Run text: " + text);
keySetIterator = keySet.iterator();
while (keySetIterator.hasNext()) {
key = keySetIterator.next();
if (text.contains(key)) {
value = replacements.get(key);
charRun.replaceText(key, value);
docRange = document.getRange();
paragraph = docRange.getParagraph(i);
charRun = paragraph.getCharacterRun(j);
text = charRun.text();
}
}
}
}
bufIStream.close();
bufIStream = null;
outputFile = new File(outputFilename);
fileOStream = new FileOutputStream(outputFile);
bufOStream = new BufferedOutputStream(fileOStream);
document.write(bufOStream);
} catch (Exception ex) {
System.out.println("Caught an: " + ex.getClass().getName());
System.out.println("Message: " + ex.getMessage());
System.out.println("Stacktrace follows.............");
ex.printStackTrace(System.out);
}
}
我用以下参数调用这个函数：
HashMap<String, String> replacements = new HashMap<String, String>();
replacements.put("AAA", "BBB");
searchAndReplace("C:/Test.doc", "C:/Test1.doc", replacements);
当 Test.doc 文件包含这样的简单行：“ AAA EEE ”时，它可以成功运行，但是当我使用复杂的文件时，它会成功读取内容并生成 Test1.doc 文件，但是当我尝试打开它时，它会给我以下错误：
Word 无法读取此文档。它可能是腐败的。尝试以下一项或多项操作： * 打开并修复文件。* 使用文本恢复转换器打开文件。(C:\Test1.doc)
请告诉我该怎么做，因为我是 POI 的初学者，我还没有找到一个好的教程。