0

编辑 如果有人至少可以告诉我在流断开连接时如何接收事件,那就太好了。

这个控件的文档简直太可怕了。我有一个具有实时视频流的应用程序,我正在寻找一种方法来使 VideoDisplay 控件在发生以下任何特定情况时恢复其连接:

  1. 应用程序启动并且流尚未在线。
  2. 该应用程序正在流式传输,并且用户已与 Internet 断开连接。
  3. 应用程序正在流式传输,视频服务器崩溃并重新启动。

我正在使用 Wowza Media Server 和 Wirecast 来测试它。1 和 3 不起作用,我不确定 2 是否起作用。我通过添加这段非常有问题的代码使第 1 项工作:

    protected function onMediaPlayerStateChange(event:MediaPlayerStateChangeEvent):void
    {
        if (event.state == MediaPlayerState.PLAYBACK_ERROR)
        {
            var videoSource:DynamicStreamingVideoSource = this.videoDisplay.source as DynamicStreamingVideoSource;

            try
            {
                this.videoDisplay.source = null;
                this.videoDisplay.source = videoSource;
            }
            catch (any:*) {}
        }
    }

正如你所看到的,我需要一个 try/catch 块,因为对source的两个调用都会导致异常,但是在这些异常之前发生的任何事情似乎都可以解决问题 #1。这并不能解决问题 #3,因为当您停止视频服务器时,显然不会发生媒体状态更改事件。

这是我的控制声明:

<s:VideoDisplay id="videoDisplay" click="onVideoStreamClick(event)" mediaPlayerStateChange="onMediaPlayerStateChange(event)" muted="{this.videoMuted}" top="10" width="280" height="220" autoPlay="true" horizontalCenter="0">
    <s:source>
        <s:DynamicStreamingVideoSource id="videoSource" streamType="live" host="{FlexGlobals.topLevelApplication.parameters.videoStreamURL}">
            <s:DynamicStreamingVideoItem id="videoItemLow" streamName="{FlexGlobals.topLevelApplication.parameters.videoLow}" bitrate="{FlexGlobals.topLevelApplication.parameters.videoLowBitrate}" />
            <s:DynamicStreamingVideoItem id="videoItemMedium" streamName="{FlexGlobals.topLevelApplication.parameters.videoMedium}" bitrate="{FlexGlobals.topLevelApplication.parameters.videoMediumBitrate}" />
            <s:DynamicStreamingVideoItem id="videoItemHigh" streamName="{FlexGlobals.topLevelApplication.parameters.videoHigh}" bitrate="{FlexGlobals.topLevelApplication.parameters.videoHighBitrate}" />
        </s:DynamicStreamingVideoSource>
    </s:source>
</s:VideoDisplay>

有谁知道如何使 VideoDisplay 从这些问题中恢复?任何帮助表示赞赏,谢谢。

4

4 回答 4

1

如果有人遇到这个问题,我就是这样解决的。您需要将视频源设置为空白图像才能停止流式传输,否则它将永远不会停止。此解决方案适用于上述所有场景:

    private function resetVideo():void
    {           
        //save current source object
        this.videoEventsDisabled = true;
        var videoSource:DynamicStreamingVideoSource = this.videoDisplay.source as DynamicStreamingVideoSource;

        try //switch to blank image, only this will stop the video stream
        {
            this.videoDisplay.source = "assets/images/video_offline.png";
        }
        catch (any:*) {}

        //wait a few seconds and reset video source
        setTimeout(resetVideoSource, 2000, videoSource);
    }

    private function resetVideoSource(videoSource:DynamicStreamingVideoSource):void
    {
        this.videoEventsDisabled = false;
        this.videoDisplay.source = videoSource;
    }

    protected function onMediaPlayerStateChange(event:MediaPlayerStateChangeEvent):void
    {
        if (this.videoEventsDisabled)
        {
            return;
        }

        //something went wrong
        if (event.state == MediaPlayerState.PLAYBACK_ERROR)
        {
            resetVideo();
        }
    }

    protected function onCurrentTimeChange(event:TimeEvent):void
    {
        if (this.videoEventsDisabled)
        {
            return;
        }

        //if there was a number before, and its suddendly NaN, video is offline
        if (isNaN(event.time) && !isNaN(this.previousVideoTime))
        {
            resetVideo();
        }
        else //store event time for future comparisons
        {
            this.previousVideoTime = event.time;
        }
    }

MXML:

<s:VideoDisplay id="videoDisplay" click="onVideoStreamClick(event)" mediaPlayerStateChange="onMediaPlayerStateChange(event)" currentTimeChange="onCurrentTimeChange(event)" muted="{this.videoMuted}" top="10" width="280" height="220" autoPlay="true" horizontalCenter="0">
    <s:source>
        <s:DynamicStreamingVideoSource id="videoSource" streamType="live" host="{FlexGlobals.topLevelApplication.parameters.videoStreamURL}">
            <s:DynamicStreamingVideoItem id="videoItemLow" streamName="{FlexGlobals.topLevelApplication.parameters.videoLow}" bitrate="{FlexGlobals.topLevelApplication.parameters.videoLowBitrate}" />
            <s:DynamicStreamingVideoItem id="videoItemMedium" streamName="{FlexGlobals.topLevelApplication.parameters.videoMedium}" bitrate="{FlexGlobals.topLevelApplication.parameters.videoMediumBitrate}" />
            <s:DynamicStreamingVideoItem id="videoItemHigh" streamName="{FlexGlobals.topLevelApplication.parameters.videoHigh}" bitrate="{FlexGlobals.topLevelApplication.parameters.videoHighBitrate}" />
        </s:DynamicStreamingVideoSource>
    </s:source>
</s:VideoDisplay>
于 2011-12-09T06:02:41.073 回答
1

作为一种变体,您可以从 NetStream 对象处理 NetStream.Play.PublishNotify。

var _source:DynamicStreamingResource;
_source = new DynamicStreamingResource("rtmp://...", StreamType.LIVE);

var streamItems:Vector.<DynamicStreamingItem> = new Vector.<DynamicStreamingItem>();
streamItems.push(new DynamicStreamingItem(streamName, 0));

_source.streamItems = streamItems;

_rtmpDynamicStreamingNetLoader = new RTMPDynamicStreamingNetLoader();
_rtmpDynamicStreamingNetLoader.addEventListener(LoaderEvent.LOAD_STATE_CHANGE, rtmpDynamicStreamingNetLoaderStateChangeHandler);

var cvp:VideoDisplay = new VideoDisplay();

_source.mediaType = MediaType.VIDEO;

var videoElement:MediaElement = new VideoElement(_source, _rtmpDynamicStreamingNetLoader);

cvp.source = videoElement;

private function rtmpDynamicStreamingNetLoaderStateChangeHandler(event:LoaderEvent):void
{
    var netStream:NetStream = event.loadTrait["netStream"] as NetStream;
    if (netStream != null && !netStream.hasEventListener(NetStatusEvent.NET_STATUS)) {
        netStream.addEventListener(NetStatusEvent.NET_STATUS, netStreamNetStatusHandler, false, 0, true);
    }
}

private function netStreamNetStatusHandler(event:NetStatusEvent):void
{
    if (event.info.code == "NetStream.Play.UnpublishNotify") {

    }
    if (event.info.code == "NetStream.Play.PublishNotify") {

    }
 }
于 2012-02-10T04:02:46.450 回答
0

我使用 Johnatan 的代码和 JayPea 的想法来解决我的问题!

我使用了 Johnatan 提供的所有内容,并在 netStreamNetStatusHandler() 中进行了以下小改动:

private function netStreamNetStatusHandler(event:NetStatusEvent):void
{
    trace(event.info.code);

    if (event.info.code == "NetStream.Play.PublishNotify")
    {
        try
        {
            cvp.source = ''; //Doesn't need to be a valid path. Empty string should suffice.
        }
        catch (error:Error)
        {
            trace('Video source error: ' + error.message);
        }

        cvp.source = videoElement;
    }
}

这会在流停止并重新启动时重置源,从而导致视频显示再次播放。

注意:视频显示的自动播放属性需要设置为“真”。

于 2016-06-15T20:53:38.200 回答
0

我知道这个问题是多年前提出的,但它仍然帮助我解决了我的问题,鼓励我深入研究 VideoDisplay 的来源(因为显然没有“干净”的解决方案 ;-(

对于那些有同样问题的人,我的“解决方案”也可能会有所帮助:

用户单击中止后,我不得不重新启动相同的视频,但随后决定再次播放。如果没有“重置” VideoDisplay,则会导致黑屏。

在我发现在 VideoDisplay 中,当在 commitProperties() 函数中没有定义 thumnailSource 时调用了内部函数“setupSource()”,这就是我解决问题的方法。

由于 setupSource() 函数不可公开访问,我使用了这个:

        myVideoDisplaySpark.enabled = false; // changes properties
        myVideoDisplaySpark.source = "";    // does not harm ;-)
        myVideoDisplaySpark.mx_internal::thumbnailSource = null; // forces a setupSource in commitProperties
        myVideoDisplaySpark.enabled = true;  // finally results in the call if setupSource

至少我是这么理解的;最后它对我有用;-)

于 2017-06-03T21:27:06.107 回答