0

我有一个名为的类,在这个类中有一个枚举值User的集合。UserRole

public class User {
    ...
    public ICollection<UserRole> UserRoles { get; private set; }
    ...
}

[Flags]
public enum UserRole {
    Beginner = 1,
    Advanced = 2,
    Expert = 4,
    Admin = 8
}

UsertoUserRole关系是多对多关系,并使用三个表(tblUser、tblRole 和 tblUserRole 仅具有 userId 和 roleId)实现。HBM如下:

<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" default-lazy="false">
   <class name="User, SampleDll" table="tblUser">
   ...
   <bag name="UserRoles" table="tblUserRole" cascade="all-delete-orphan" fetch="join">
      <key column="UserId"/>
      <element column="RoleId" type="UserRole, SampleDll" />      
   </bag> 
   ...
   </class> 
</hibernate-mapping> 

现在我想创建一个具有相同语义的标准

select u.* from tblUser u 
left join tblUserRole ur on ur.UserId = u.UserId
where ur.RoleId = @USER_ROLE

是否可以在没有单独的枚举映射文件的情况下实现这样的条件(使用 queryOver 或分离的条件)UserRole

提前感谢您的提示。

先生

4

1 回答 1

0

您已经有一个基本上已经是值集合的标志枚举。为此,您甚至不需要表 UserRoles 和 Roles,只需 User 中的一个简单列就足够了

[Flags]
public enum UserRoles {
    Beginner = 1,
    Advanced = 2,
    Expert = 4,
    Admin = 8
}

public virtual UserRoles Roles { get; private set; }

<property name="Roles" column="UserRoles"/>

当你真的想要这样的东西时:

public class User {
    ...
    public virtual ICollection<UserRole> Roles { get; private set; }
    ...
}

public class UserRole {
    public virtual int Id { get; set; }

    ...
}

然后

<bag name="Roles" table="tblUserRole" cascade="none"> <!-- none because Roles are somewhat static not per user -->
   <key column="UserId"/>
   <many-to-many column="RoleId" class="UserRole, SampleDll" />      
</bag>

<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
  <class name="UserRole" table="Roles">
    <id name="Id"/>
    <!--additional properties-->
  </class>
</hibernate-mapping>
于 2011-12-07T09:57:45.410 回答