我感觉很笨。
public class Uber
{
public Foo Foo { get; set; }
public Bar Bar { get; set; }
}
public class Foo
{
public string Name { get; set; }
}
...
var ubercharged = session.CreateCriteria(typeof(Uber))
.Add(Expression.Eq("Foo.Name", "somename"))
.UniqueResult<Uber>();
return ubercharged;
这会引发“无法解析属性”错误。
我究竟做错了什么?我想查询一个 Uber 对象,该对象的属性 Foo 的名称为“somename”。
使用流利的 nhibernate 更新了现实生活中的示例,存储库调用:
public UserPersonalization GetUserPersonalization(string username)
{
ISession session = _sessionSource.GetSession();
var personuser = session.CreateCriteria(typeof(UserPersonalization))
.Add(Expression.Eq("User.Username", username))
.UniqueResult<UserPersonalization>();
return personuser;
}
类/映射:
public class User
{
public virtual Guid UserId { get; set; }
public virtual string Username { get; set; }
public virtual string Email { get; set; }
public virtual string PasswordHash { get; set; }
public virtual string PasswordSalt { get; set; }
public virtual bool IsLockedOut { get; set; }
public virtual bool IsApproved { get; set; }
}
public class Person
{
public virtual int PersonId { get; set; }
public virtual string Name { get; set; }
public virtual Company Company { get; set; }
}
public class UserPersonalization
{
public virtual int UserPersonalizationId { get; set; }
public virtual Person Person { get; set; }
public virtual User User { get; set; }
}
public class UserMap : ClassMap<User>
{
public UserMap()
{
Id(x => x.UserId).GeneratedBy.Guid().ColumnName("UserId");
Map(x => x.Username);
Map(x => x.PasswordHash);
Map(x => x.PasswordSalt);
Map(x => x.Email);
Map(x => x.IsApproved);
Map(x => x.IsLockedOut);
}
}
public class UserPersonalizationMap : ClassMap<UserPersonalization>
{
public UserPersonalizationMap()
{
WithTable("UserPersonalization");
Id(x => x.UserPersonalizationId).ColumnName("UserPersonalizationId");
References(x => x.Person).ColumnName("PersonId");
References(x => x.User).ColumnName("UserId");
}
}
public class PersonMap : ClassMap<Person>
{
public PersonMap()
{
Id(x => x.PersonId).ColumnName("PersonId");
Map(x => x.Name);
References(x => x.Company).ColumnName("CompanyId");
}
}