c++ - 如何一步获得商和余数？

Question

可能重复：
同时除法和获取余数？

是否可以在一个步骤中同时获得整数除法的商和余数，即不执行两次整数除法？

Answer 1

div会这样做。请参阅参考和示例：

/* div example */
#include <stdio.h>
#include <stdlib.h>

int main ()
{
  div_t divresult;
  divresult = div (38,5);
  printf ("38 div 5 => %d, remainder %d.\n", divresult.quot, divresult.rem);
  return 0;
}

输出：

38 div 5 => 7, remainder 3.

编辑：

C规范说：

7.20 一般公用事业

The types declared are size_t and wchar_t (both described in 7.17),
div_t
which is a structure type that is the type of the value returned by the div function,
ldiv_t
which is a structure type that is the type of the value returned by the ldiv function, and
lldiv_t
which is a structure type that is the type of the value returned by the lldiv function.

...但它没有说明的定义div_t是什么。

Answer 2

Yes, there is a standard function called div() (and ldiv, and maybe even lldiv) that does this.