4

在以下示例中,我得到:

error C2300: 'UnmanagedClass' : class does not have a finalizer called '!SmartPointer'

如果我删除 operator->,这个错误就会消失。有人可以解释为什么会这样吗?

// Unmanaged class.
class UnmanagedClass { };

public ref class SmartPointer {
public:
    SmartPointer(UnmanagedClass* u) : m_ptr(u) { }
    ~SmartPointer() { this->!SmartPointer(); }
    !SmartPointer() { delete m_ptr; }

    // This line triggers C2300.
    UnmanagedClass* operator->() { return m_ptr; }
};

int main() {
    SmartPointer^ s = gcnew SmartPointer(new UnmanagedClass);
}
4

1 回答 1

5

您正在覆盖 -> 运算符,因此当您这样做时:

~SmartPointer() { this->!SmartPointer(); }

你有效地打电话

~SmartPointer() { m_ptr->!SmartPointer(); }

不过,我相信您可以通过以下方式解决此问题:

~SmartPointer() { (*this).!SmartPointer(); }
于 2009-05-06T17:11:29.513 回答