php - PHP 从 URL 字符串获取参数（不是当前页面）

Question

我知道您可以轻松地从当前所在的页面获取参数，但是您可以轻松地从任何 URL 字符串中获取相同的参数吗？

我需要从像https://market.android.com/details?id=com.zeptolab.ctr.paid?t=W251bGwsMSwxLDIxMiwiY29tLnplcHRvbGFiLmN0ci5wYWlkIl0.

我怎样才能用 PHP 做到这一点？是否有内置函数，或者我必须使用正则表达式？

Answer 1

您可以使用parse_url和parse_str的组合：

$url = 'https://market.android.com/details?id=com.zeptolab.ctr.paid?t=W251bGwsMSwxLDIxMiwiY29tLnplcHRvbGFiLmN0ci5wYWlkIl0';
$arr = parse_url($url);
parse_str($arr['query']);
echo $id; //com.zeptolab.ctr.paid?t=W251bGwsMSwxLDIxMiwiY29tLnplcHRvbGFiLmN0ci5wYWlkIl0

Answer 2

Yes you can.

parse_url()

From the PHP docs:

<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';
print_r(parse_url($url));
echo parse_url($url, PHP_URL_PATH);
?>

The above example will output:

Array
(
    [scheme] => http
    [host] => hostname
        [user] => username
    [pass] => password
    [path] => /path
    [query] => arg=value
    [fragment] => anchor
)

/path

Answer 3

There's parse_url():

function extractGETParams($url)
{
  $query_str = parse_url($url, PHP_URL_QUERY);
  $parts = explode('&', $query_str);
  $return = array();

  foreach ( $parts as $part )
  {
    $param = explode('=', $part);
    $return[$param[0]] = $param[1];
  }

  return $return;
}

$url = 'http://username:password@hostname/path?arg=value&arg2=value2#anchor';

var_dump( extractGETParams($url) );

On Codepad.org: http://codepad.org/mHXnOYlc

Answer 4

You can use parse_str(), and then access the variable $id.