2

我正在尝试做的事情


大家好,我正在为我的一个朋友创建一个应用程序,我只是在我的应用程序中显示他的频道。我通过 JSON 获得视频数据。

现在我发现了一个问题。当我通过 SimpleListAdapter 将数据填充到我的 ListView 中并尝试通过 OnItemClickListner 获取它并检索它们时,lv.getItemAtPosition(position);我得到了存储在特定行中的所有数据。但我只需要我保存在该字段中的链接/网址。

问题


就像您阅读的那样,我在 ListView 中获得了不止一个信息,确切地说是有四个字符串(Thumb、Title、Content、Link)。但是我只需要获取链接的字符串,我该怎么做,在这里你可以找到代码。

代码


test2.java

package de.stepforward;

import java.io.BufferedReader;
import java.io.FileOutputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;


import org.apache.http.NameValuePair;
import org.json.JSONArray;
import org.json.JSONObject;



import android.app.ListActivity;
import android.database.Cursor;
import android.media.RingtoneManager;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.AdapterView;
import android.widget.ListAdapter;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.SimpleCursorAdapter;
import android.widget.TextView;
import android.widget.Toast;

public class test2 extends ListActivity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);


    String result = "";
    String line = null;
    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();


    //get the Data from URL
    try{
    URL url = new URL("http://gdata.youtube.com/feeds/mobile/users/TheStepForward/uploads?alt=json&format=1"); 

    URLConnection conn = url.openConnection();
    StringBuilder sb = new StringBuilder();
    BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));

    //read d response till d end
    while ((line = rd.readLine()) != null) {
    sb.append(line + "\n");
    }
    result = sb.toString();
    Log.v("log_tag", "Append String " + result);
    } catch (Exception e) {
    Log.e("log_tag", "Error converting result " + e.toString());
    }

    try{
        JSONObject json = new JSONObject(result);
        JSONObject feed = json.getJSONObject("feed");
        JSONArray entrylist = feed.getJSONArray("entry");

        for(int i=0;i<entrylist.length();i++){
            //Get Title
            JSONObject movie = entrylist.getJSONObject(i);
            JSONObject title = movie.getJSONObject("title");
            String txtTitle = title.getString("$t");
            Log.d("Title", txtTitle);

            //Get Description
            JSONObject content = movie.getJSONObject("content");
            String txtContent = content.getString("$t");
            Log.d("Content", txtContent);

            //Get Link
            JSONArray linklist = movie.getJSONArray("link");
            JSONObject link = linklist.getJSONObject(0);
            String txtLink = link.getString("href");
            Log.d("Link", txtLink);


            //Get Thumbnail
            JSONObject medialist = movie.getJSONObject("media$group");
            JSONArray thumblist = medialist.getJSONArray("media$thumbnail");
            JSONObject thumb = thumblist.getJSONObject(2);
            String txtThumb = thumb.getString("url");
            Log.d("Thumb", txtThumb.toString());


            //String Array daraus machen und in Hashmap füllen
            HashMap<String, String> map = new HashMap<String, String>();
            map.put("Thumb", txtThumb);
            map.put("Title", txtTitle);
            map.put("Content", txtContent);
            map.put("Link", txtLink);
            mylist.add(map);

        }
        //ListView füllen
        ListAdapter adapter = new SimpleAdapter(this, mylist , R.layout.lit, 
                new String[] { "Thumb","Title","Content","Link"}, 
                new int[] { R.id.img_video,R.id.txt_title,R.id.txt_subtitle});      
        setListAdapter(adapter);


        //OnClickLister um Youtube-Video zu öffnen
        final ListView lv = getListView();
            lv.setOnItemClickListener(new OnItemClickListener(){
                public void onItemClick(AdapterView<?> parent, View v, int position, long id) {

                    lv.getItemAtPosition(position);

                }
            });



    }catch (Exception e) {
        Log.e("log_tag", "Error converting result " + e.toString());
        }
}
}

先感谢您

4

5 回答 5

7
 final ListView lv = getListView();
            lv.setOnItemClickListener(new OnItemClickListener(){
                public void onItemClick(AdapterView<?> parent, View v, int position, long id) {

                   Map<String, String> map = mylist.get(position);
                   String link = map.get("Link");


                }
            });
于 2011-11-28T11:11:03.437 回答
1

更好的方法是将您的信息包装在一个中Object并从互联网下载数据并制作一个Object并将其添加到任何ArrayList.

例如:

您将创建一个 Java 对象类。说:VideoInfo

public class VideoInfo
{
     String title, content, link, thumb;
     // define there setter getter
     // also a constructor with these params 
     public VideoInfo(String title,String content,String link,String thumb)
     {
          //set Values accordingly
     }
}

做一个班级水平ArrayList

ArrayList<VideoInfo> myList = new ArrayList<VideoInfo>();

当您从服务器获取数据时,解析它并像这样保存它:

myList.add(new VideoInfo(txtTitle, txtContent, txtLink, txtThumb));

您将需要自定义Adapter(例如 override getView()以从您的自定义 Ojbect ( VideoInfo) 中设置数据。

然后在你ListActivity的里面OnItemClickListener你会像这样得到你想要的对象:

public void onItemClick(AdapterView<?> parent, View v, int position, long id) {
    // you have class level ArrayList myList.
    myList.get(position).getLink();  //getLink() will be the getter of you field link in VideoInfo
}
于 2011-11-28T11:09:01.230 回答
0
lv.setOnItemClickListener(new OnItemClickListener(){

            public void onItemClick(AdapterView<?> parent, View v, int position, long id) {

            HashMap<String, String> selectedHashMapObject = (HashMap<String, String>)lv.getItemAtPosition(position);

            String selectedLink = selectedHashMapObject.get("Link"); 
}
于 2011-11-28T11:19:16.853 回答
0

例如,您可以执行以下类似操作:

for(int i = 0; i < ((ListView)lv).getItemCount(); i++){
    Map<String, String> currentView =  (Map<String, String>) ((ListView)lv).getItemAtPosition(i);
    String cVId = currentView.get("id");
}
于 2013-01-08T15:14:17.057 回答
-1

我认为您可以使用此 http://developer.android.com/reference/android/widget/CursorAdapter.html#getItem(int )。

Cursor cursor = (Cursor) simple.getItem(position);

// 从游标中检索数据

于 2011-11-28T10:56:45.363 回答