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class A : public QObject{

  Q_OBJECT

signals:
  void a_sig();

public:
  A(){ }

public slots:
  void begin(){
    QObject::connect(&_timer, SIGNAL(timeout()), this, SIGNAL(a_sig()));
    _timer.start(1000); 
  }

private:
  QTimer _timer;
};


class B : public QObject{

  Q_OBJECT

public:
  B(){ value = 0; }

public slots:
  void b_slot(){

    ++value;
    QFile file("out.txt");
    file.open(QIODevice::WriteOnly);
    QTextStream out(&file);
    out << value << "\n";
    file.close();
  }

private:
  int value;
};

int main(int argc, char **argv){

  QCoreApplication app(argc, argv);

  A a;
  B b;
  QThread aThread;
  QThread bThread;

  QObject::connect(&aThread, SIGNAL(started()), &a, SLOT(begin()));
  QObject::connect(&a, SIGNAL(a_sig()), &b, SLOT(b_slot()));

  a.moveToThread(&aThread);
  b.moveToThread(&bThread);

  aThread.start();
  bThread.start();

  return app.exec();
}

我试图理解为什么b_slot()没有被调用。谁能解释发生了什么,为什么b_slot()没有被调用?

4

2 回答 2

5

_timer问题是类成员的所有权A

由于您没有显式初始化它,因此它在没有父对象的情况下被初始化。因此,a.moveToThread(&aThread)没有将计时器移至aThread,之后事情变得混乱。

将 的构造函数更改A为:

A() : _timer(this) {}

b_slot()会被召唤。

于 2011-11-27T11:40:05.753 回答
2

问题是当 objecta被移动到 时aThread_timerobject 仍然属于原来的主线程。尝试像这样初始化_timer内部begin方法:

  void begin() {
    _timer = new QTimer;
    QObject::connect(_timer, SIGNAL(timeout()), this, SIGNAL(a_sig()));
    _timer->start(1000); 
  }

private:

  QTimer *_timer;
于 2011-11-27T11:40:31.193 回答