我正在尝试使用gpg.exe --passphrase-file my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg（没有 --batch 和 --yes 选项）进行解密。如果有人愿意将其用于测试，我还将提供加密命令gpg.exe --passphrase-file ..\BE\src\my.passphrase --symmetric --output MTR241_20111124.htm.gpg MTR241_20111124.htm。
有两种情况。案例 1：输出目录中不存在 MTR241_20111124.htm 文件。exec 的命令提示符和捕获的输出流都提供相同的输出。
C:\Eclipse\workspace2\sync_inbox>gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
Reading passphrase from file descriptor 3
gpg: CAST5 encrypted data
gpg: encrypted with 1 passphrase
gpg: WARNING: message was not integrity protected
java exec 和命令提示符会打印相同的消息。
C:\Eclipse\workspace2\sync_inbox>gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
inp>gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
gpg: CAST5 encrypted data
gpg: encrypted with 1 passphrase
gpg: WARNING: message was not integrity protected
到目前为止足够好
案例2：当输出文件在命令提示符中已按预期存在时，它询问我是否要替换。
C:\Eclipse\workspace2\sync_inbox>gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
Reading passphrase from file descriptor 3
gpg: CAST5 encrypted data
gpg: encrypted with 1 passphrase
File `MTR241_20111124.htm' exists. Overwrite? (y/N) y
gpg: WARNING: message was not integrity protected
但是这个输出来自在第一行之后挂起的java程序。它不会在控制台上打印任何行。如果我在控制台中输入“y”，它不接受输入和处理。它只是挂起。我必须手动终止进程 taskkill /F /IM gpg.exe 只有这样 Java 控制台程序才能接受更多命令和进程。
C:\Eclipse\workspace2\sync_inbox>gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
inp>gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
gpg.exe --passphrase-file ..\BE\src\my.passphrase --decrypt --output MTR241_20111124.htm MTR241_20111124.htm.gpg
--hangs here--
正常的交互式命令当然可以工作，例如：
F:\eclipse\workspace\HTMLProcessor\BEQuery>copy hello.txt world.txt
inp>copy hello.txt world.txt
copy hello.txt world.txt
Overwrite world.txt? (Yes/No/All): y
inp>y
y
1 file(s) copied.
所以这是我的问题，为什么只有在询问是否替换现有输出文件时才捕获gpg的输出流。
我已经尝试过 Runtime.exec()、ProcessBuilder、Plexus-Utils、ExpectJ、Ant 在 Java 程序中运行这个 gpg.exe，它们都显示相同的结果，在这种特殊情况下无法捕获进程的输出流。我什至尝试编写一个.bat文件来运行，gpg --decrypt但即便如此，它也无法在上述特殊情况下捕获输出流。
我认为这很重要，gpg.exe 的来源。好吧，我在便携式 git 发行版中得到了它，在 bin 文件夹中 gpg.exe 可用。
我的问题变得很长很无聊，但对于那些喜欢指出错误的人来说仍然是java代码
package com.ycs.ezlink.scheduler.cmd;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import org.apache.log4j.Logger;
public class CmdRunner {
private static Logger logger = Logger.getLogger(CmdRunner.class);
static class StreamGobbler extends Thread
{
InputStream is;
String type;
StreamGobbler(InputStream is, String type)
{
this.is = is;
this.type = type;
}
public void run() {
try {
System.out.println("in run!");
System.out.println(type);
final byte[] buffer = new byte[1];
for (int length = 0; (length = is.read(buffer)) != -1;) {
System.out.write(buffer, 0, length);
}
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
}
public static int process(String cmd){
int exitVal = 0;
try {
Runtime rt = Runtime.getRuntime();
Process proc = rt.exec(cmd);
// any error message?
StreamGobbler errorGobbler = new
StreamGobbler(proc.getErrorStream(), "ERROR");
// any output?
StreamGobbler outputGobbler = new
StreamGobbler(proc.getInputStream(), "OUTPUT");
// kick them off
errorGobbler.start();
outputGobbler.start();
// any error???
System.out.println("Waiting for cmd process to complete " );
exitVal = proc.waitFor();
System.out.println("ExitValue: " + exitVal);
} catch (IOException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
return exitVal;
}
public static void main(String[] a) throws IOException, InterruptedException, TimeoutException, ExpectJException {
String gzipCmd = "gpg.exe --passphrase-file C:/Eclipse/workspace2/BE/src/my.passphrase --decrypt --output C:/Eclipse/workspace2/sync_inbox/MTR241_20111124.htm C:/Eclipse/workspace2/sync_inbox/MTR241_20111124.htm.gpg";
//CmdRunner.process(gzipCmd); ///--fails
//ProcessBuilder pb = new ProcessBuilder("gpg", "--passphrase-file", "C:/Eclipse/workspace2/BE/src/my.passphrase",
"--decrypt","--output","C:/Eclipse/workspace2/sync_inbox/MTR241_20111124.htm",
"C:/Eclipse/workspace2/sync_inbox/MTR241_20111124.htm.gpg"); ///--fails
ProcessBuilder pb = new ProcessBuilder ("cmd");
pb.redirectErrorStream(true);
Process process = pb.start();
OutputStream stdin = process.getOutputStream ();
InputStream stderr = process.getErrorStream ();
InputStream stdout = process.getInputStream ();
StreamGobbler errorGobbler = new StreamGobbler(stderr, "ERROR");
errorGobbler.start();
StreamGobbler stdoutGobbler = new StreamGobbler(stdout, "DEBUG");
stdoutGobbler.start();
BufferedReader scan = new BufferedReader(new InputStreamReader(System.in));
String line;
while ((line = scan.readLine())!= null) {
String input = line;
System.out.println("inp>"+input);
if (input.trim().equals("exit")) {
stdin.write("exit\r\n".getBytes());
stdin.flush();
break;
} else {
stdin.write((input+"\r\n").getBytes());
stdin.flush();
}
}
System.out.println("exited..");
int returnCode = process.waitFor();
System.out.println(returnCode);
}
}
最后一句话，如果我使用该gpg --batch选项，它不再提示y/N输入，所以它运行顺利。但我只是想知道，为什么会有这个问题。虽然我感觉 gpg.exe 最初是为类 Unix/Linux 平台编写的，所以可能会有一些输入输出文件重定向，但我想进一步了解它的根本原因，以便下次我知道是什么寻找。