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我有下一个 WPF 树视图:

        <TreeView HorizontalAlignment="Left" Margin="6,0,0,32" Name="tvProductos" Width="158">
            <TreeViewItem Header="Securities" IsExpanded="True" FontWeight="Bold">
                <TreeViewItem Header="Country" Name="Country" FontWeight="Normal" />
                <TreeViewItem Header="Currency" Name="Currency" FontWeight="Normal" />
                <TreeViewItem Header="Type" Name="Type" FontWeight="Normal" />
                <TreeViewItem Header="ISIN" Name="ISIN" FontWeight="Normal" />
                <TreeViewItem Header="Description" Name="Description" FontWeight="Normal" />
            </TreeViewItem>
            <TreeViewItem Header="Issuer" IsExpanded="True" FontWeight="Bold">
                <TreeViewItem Header="Name" Name="IssuerName" FontWeight="Normal" />
                <TreeViewItem Header="Type" Name="IssuerType" FontWeight="Normal" />
                <TreeViewItem Header="Market" Name="IssuerMarket" FontWeight="Normal" />
            </TreeViewItem>
        </TreeView>

这个结构是固定的。然后我使用如下代码绑定低级 TreeViewItems:

        Country.ItemsSource = (from d in db.PAISES
                               join p in db.PRODUCTOS on d.IDPAIS equals p.IDPAIS
                               select d.NOMBREPAIS).Distinct();
        Currency.ItemsSource = (from d in db.DIVISAS
                                join p in db.PRODUCTOS on d.IDDIVISA equals p.IDDIVISA
                                select d.NOMBREDIVISA).Distinct();
        Type.ItemsSource = (from d in db.TIPOSPRODUCTO
                            join p in db.PRODUCTOS on d.IDTIPOPRODUCTO equals p.IDTIPOPRODUCTO
                            select d.NOMBRETIPOPRODUCTO).Distinct();
        ...

问题是我需要在每个节点(低级和高级)上添加一个复选框。我一直在寻找解决方案,最好的解决方案是使用 HierarchicalDataTemplate。但是我从来没有找到同时具有固定节点和动态节点的示例。我尝试了几个示例,但无法解决。

你能帮我解决这个问题吗?

先感谢您。

亲切的问候。

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1 回答 1

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我这样做的方式是使用一个帮助类来表示可以检查的项目(有些人称之为“视图模型”):

public class SelectableItem
{
    public bool IsSelected { get; set; }
    public string Label { get; set; }
}

这允许您DataTemplate为此特定类型指定 a:

<TreeView HorizontalAlignment="Left" Margin="6,0,0,32" Name="tvProductos" Width="158">
    <TreeView.Resources>
        <DataTemplate DataType="{x:Type local:SelectableItem}" xmlns:local="clr-namespace:WpfApplication1">
            <StackPanel Orientation="Horizontal">
                <CheckBox IsChecked="{Binding IsSelected}" />
                <TextBlock Text="{Binding Label}" />
            </StackPanel>
        </DataTemplate>
    </TreeView.Resources>
    <TreeViewItem Header="Securities" IsExpanded="True" FontWeight="Bold">
        <TreeViewItem Header="Country" Name="Country" FontWeight="Normal" />
        <TreeViewItem Header="Currency" Name="Currency" FontWeight="Normal" />
        <TreeViewItem Header="Type" Name="Type" FontWeight="Normal" />
        <TreeViewItem Header="ISIN" Name="ISIN" FontWeight="Normal" />
        <TreeViewItem Header="Description" Name="Description" FontWeight="Normal" />
    </TreeViewItem>
    <TreeViewItem Header="Issuer" IsExpanded="True" FontWeight="Bold">
        <TreeViewItem Header="Name" Name="IssuerName" FontWeight="Normal" />
        <TreeViewItem Header="Type" Name="IssuerType" FontWeight="Normal" />
        <TreeViewItem Header="Market" Name="IssuerMarket" FontWeight="Normal" />
    </TreeViewItem>
</TreeView>

您需要做的就是稍微修改您的数据源:

Country.ItemsSource = (from d in db.PAISES
                       join p in db.PRODUCTOS on d.IDPAIS equals p.IDPAIS
                       select new SelectableItem { Label = d.NOMBREPAIS }).Distinct();

这应该可以解决问题。

于 2011-11-22T09:16:03.537 回答