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我正在向服务器发布一些数据，但我收到了{"status":false,"error":"Invalid API Key."}来自服务器的响应。我的 API 密钥是正确的，但我不知道问题出在哪里。请朋友帮帮我。我尝试了很多，但我没有找到解决方案。我使用以下代码将数据发布到服务器。

public void tryingOne(String dtl){

     HttpConnection httpConn = null;
    InputStream is = null;
    OutputStream os = null;

 String url="http://api.geanly.in/ma/index?API-Key="+apikey;

    String details = "&orderInfo={\"booking\":{\"restaurantinfo\":{\"id\":\"5722\"},\"referrer\":{\"id\": \"9448476530\" }, \"bookingdetails\":{\"instructions\":\"Make the stuff spicy\",\"bookingtime\": \"2011-11-09 12:12 pm\", \"num_guests\": \"5\"}, \"customerinfo\":{\"name\":\"Vinodh SS\",   \"mobile\":\"9345245530\",  \"email\": \"vind@gmail.com\",  \"landline\":{ \"number\":\"0908998393\",\"ext\":\"456\"}}}}";
    try {

        System.out.println("url@@@@"+url);
        httpConn = (HttpConnection) Connector.open(url);
        httpConn.setRequestMethod(HttpConnection.POST);

       DataOutputStream outStream = new DataOutputStream(httpConn.openDataOutputStream());
        outStream.write(details.getBytes(),0,details.length());
        outStream.flush();
        outStream.close();

  //Reading Resp. from server
        StringBuffer sb = new StringBuffer();
        is = httpConn.openDataInputStream();
        int chr;
        while ((chr = is.read()) != -1) {
            sb.append((char) chr);
        }


        System.out.println("Response from srvr " + sb.toString());

    } catch (IOException ex) {
        ex.printStackTrace();
    } finally {
        if (is != null) {
            try {
                is.close();
            } catch (IOException ex) {
                ex.printStackTrace();
            }
        }
        if (os != null) {
            try {
                os.close();
            } catch (IOException ex) {
                ex.printStackTrace();
            }
        }
        if (httpConn != null) {
            try {
                httpConn.close();
            } catch (IOException ex) {
                ex.printStackTrace();
            }
        }
    }
}

请帮助我的朋友...谢谢

4

2 回答 2

1

您需要修剪变量“apikey”。

我在连接 Picasa 服务器时遇到了同样的问题。

于 2011-11-15T06:43:43.623 回答
1

要使用本教程中HttpConnection的类发送数据。它还从服务器获取响应。

于 2011-11-15T05:57:10.400 回答