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我正在从文件中读取表示并将其存储在邻接列表中。然后我以“graphviz 格式”输出图形并在图形上执行 MST 算法。最后，我以“graphviz 格式”输出 MST。我在 C++ 中这样做。

我的主要问题是算法。我正在实现 Kruskals 算法并且排序功能不起作用。

当我编译它时，我得到这个错误：

从 'void std::sort(_RandomAccessIterator, _RandomAccessIterator, _Compare) 实例化 [with _RandomAccessIterator = __gnu_cxx::__normal_iterator*, std::vector, std::allocator > > >, _Compare = bool (*)(Edges, Edges)] '</p>

这是我的代码：

#include <iostream>
#include <iomanip>
#include <fstream>
#include <map>
#include <vector>
#include <algorithm>
#include <cstdlib>  
#include <utility>   


using namespace std;


#define egdes pair<int ,int >
#define MAX 9

struct Edges
{
    int weight;
    int first,second;
    char begin,end;
};

    bool EdgeLess(Edges oneE,Edges twoE)
     {
        return oneE.weight < twoE.weight;
     }  

vector<pair<int ,Edges > > graph,MST;
int parent[MAX],total ;


bool openInputFile(ifstream &inFile,char* argv);
bool openOutputFile(ofstream &outFile,char* argv);
void readInputFile(ifstream &inFile,vector<Edges> &graph);
int findSet(int x,int *parent);
void kruskals();
void makeSet();
bool compareEdgW(Edges oneE,Edges twoE);

int main (int argc,char **argv)
{

    ifstream inFile;
    ofstream outFile;
    int u,v,w;
     int nodeCount;
    int edgeCount;
    char nodeName;
    Edges edge;

    vector<Edges> graph;

        cout<<"hey"<<endl;
 if(openInputFile(inFile,argv[1]) && openOutputFile(outFile,argv[2]))
    {
        readInputFile(inFile,graph);

        outFile.close();
    }

    inFile >> nodeCount;
    inFile >> edgeCount;

    for( int i = 0;i < edgeCount; i++)
    {
        cin >> u >> v >> w ; 
//        graph.push_back(pair<int ,Edges >(w,edges(u,v)));
        graph.push_back(edge);
    }

    kruskals();

    makeSet();  
    return 0;
}


bool openInputFile(ifstream &inFile,char* argv)
{
    inFile.open("input.txt");
    if(!inFile)
    {
        cout<<"Oops!Input file did not open.\n";
        cout<<"Terminating the program.\n";
        return false;
    }
    return true;
}
bool openOutputFile(ofstream &outFile,char* argv)
{
    outFile.open("output.gv");
    if(!outFile)
    {
        cout<<"Hey!Oops!Input file did not open.\n";
        cout<<"Terminating the program.\n";
        return false;
    }
    return true;
}
void readInputFile(ifstream &inFile,vector<Edges> &graph)
{
    int nodeCount;
    Edges edge;

    inFile >>nodeCount;

    char nodeName;

    for (int i = 0;i < nodeCount;i++)
    {
        inFile >> nodeName;
//        graph.insert(make_pair(nodeName,vector<Edges>()));

    }
    int edgeCount;
    inFile >> edgeCount;

    for (int i = 0;i < edgeCount;i++)
    {
  //      inFile >>nodeName;
        Edges edge;
        inFile >> edge.begin;
        inFile >> edge.weight;
        inFile >> edge.end;
        graph.push_back(edge);

    }

}
int findSet(int x,int *parent)
{
    if( x != parent[x])
        parent [x] = findSet(parent[x],parent);
    return parent[x];

}

void kruskals()
{
    int pu;
    int pv;
    int edgeCount;

    sort(graph.begin(),graph.end (),EdgeLess);
    for (int i = 0;i < edgeCount; i++) 
    {
        pu = findSet(graph[i].second.first,parent);
        pv = findSet(graph[i].second.second,parent);
        if(pu != pv)
        {   
            MST.push_back(graph[i]);
            total += graph[i].first;
            parent[pu] = parent[pv];
        }
    }
}
void makeSet()
{
    unsigned long sizeNum;
    sizeNum = MST.size();
    for(int i = 0;i < sizeNum;i++)
    {
        cout<< MST[i].second.first <<endl;
        cout<< MST[i].second.second <<endl;
        cout<< MST[i].first <<endl;
    }
        cout << total <<endl;
}
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1 回答 1

2

问题是graph调用范围内的kruskals是全局的graph，声明为vector<pair<int,Edges> >. 所以你不能用EdgeLess它来排序，因为EdgeLess比较的是Edgeses，而不是pair<int,Edges>es。

我是否可以建议将一个名为 type 的全局变量与名为graphtype的vector<pair<int,Edges> >各种局部变量一起命名graph是不必要的混淆vector<pair<Edges> >？如果您真的需要所有这些不同的变量，以及它们当前的作用域和当前类型，那么您可能应该将全局变量重命名为表明它是全局的。

于 2011-11-11T21:34:09.323 回答