您能否采用将测量值与每个段位置逐个位置进行匹配并计算每个位置的差异的方法。然后将测量值沿一个位置滑动并计算差异。然后找出哪个幻灯片位置得分最低。对每个产品都这样做，然后您就知道测量结果与哪个产品最接近。
测试表和数据：
CREATE TABLE [dbo].[Segment]
(
[ProductId] INT,
[Position] INT,
[Value] INT
)
INSERT [dbo].[Segment]
VALUES (1, 1, 300),
(1, 2, 5000),
(1, 3, 900),
(1, 4, 400),
(1, 5, 800),
(2, 1, 400),
(2, 2, 6000),
(2, 3, 1000),
(2, 4, 500),
(2, 5, 900),
(3, 1, 400),
(3, 2, 5400),
(3, 3, 900),
(3, 4, 400),
(3, 5, 900)
CREATE TABLE #Measurement
(
[Position] INT,
[Value] INT
)
INSERT #Measurement
VALUES (1, 5400),
(2, 900),
(3, 400)
如您所见，测量结果与第三个产品（的一个子集）完全匹配。
一些帮手：
CREATE TABLE #ProductSegmentCount
(
[ProductId] INT,
[SegmentCount] INT
)
INSERT #ProductSegmentCount
SELECT [ProductId], MAX([Position])
FROM [dbo].[Segment]
GROUP BY [ProductId]
DECLARE @MeasurementSegmentCount INT = (SELECT MAX([Position]) FROM #Measurement)
一个递归公用表表达式，用于显示按最接近匹配排序的产品：
;WITH [cteRecursive] AS
(
SELECT s.[ProductId],
0 AS [RecursionId],
m.[Position] AS [MeasurementPosition],
s.[Position] AS [SegmentPosition],
ABS(m.[Value] - s.[Value]) AS [Difference]
FROM #Measurement m
INNER JOIN [dbo].[Segment] s
ON m.[Position] = s.[Position]
UNION ALL
SELECT s.[ProductId],
[RecursionId] + 1 AS [RecursionId],
m.[Position],
s.[Position],
ABS(m.[Value] - s.[Value]) AS [Difference]
FROM [cteRecursive] r
INNER JOIN #Measurement m
ON m.[Position] = r.[MeasurementPosition]
INNER JOIN [dbo].[Segment] s
ON r.[ProductId] = s.[ProductId]
AND m.[Position] + (r.[RecursionId]) = s.[Position]
INNER JOIN #ProductSegmentCount psc
ON s.[ProductId] = psc.[ProductId]
WHERE [RecursionId] <= ABS(@MeasurementSegmentCount - psc.[SegmentCount])
)-- select * from [cteRecursive] where [ProductId] = 3 order by RecursionId, SegmentPosition
, [cteDifferences] AS
(
SELECT [ProductId], [RecursionId], SUM([Difference]) AS [Difference]
FROM [cteRecursive]
GROUP BY [ProductId], [RecursionId]
)-- select * from [cteDifferences]
SELECT [ProductId], MIN([Difference]) AS [Difference]
FROM [cteDifferences]
GROUP BY [ProductId]
ORDER BY MIN([Difference])
OPTION (MAXRECURSION 0)