1

我试图在一个循环中将日期重复一个月固定次数。如果日期是有效日期，它只会回显日期，否则它将跳过日期。例如，如果“2012-02-30 10:10:00”进入循环，它将被忽略并跳过，并继续进行下一次迭代。

以下代码适用于 start_date “2011-11-07 10:15:00”，但是当我将其更改为注释为“2011-11-30 10:15:00”的 start_date 时，它​​会在 24 小时后添加跳过一次迭代。

我不确定我哪里出错了。

<?php
//$start_date = "2011-11-30 10:15:00";
$start_date = "2011-11-07 10:15:00";
$no_of_repeat = 15;
$repeat_timing = 0;
for($x=0; $x<$no_of_repeat; $x++) {
    $start_date = date('Y-m-d G:i:s',(strtotime($start_date) + ($repeat_timing)));
    if(date("m",strtotime($start_date)) != 12) {
        $next_month = date('m',strtotime($start_date)) + 1;
        $year = date('Y',strtotime($start_date));
    } else {
        $next_month = 1 ;
        $year = date('Y',strtotime($start_date)) + 1;
    }
    $day = date("d",strtotime($start_date));
    $next_date =
    $year."-".
    $next_month."-".
    $day." ".
    date("G",strtotime($start_date)).":".
    date("i",strtotime($start_date)).":".
    date("s",strtotime($start_date));
    if(checkdate($next_month,$day,$year))
        $repeat_timing = strtotime($next_date) - strtotime($start_date);
    else
        continue;   
    echo $next_date."<br />";
}
?>

注释 start_date 的预期结果如下：

2011-12-30 10:15:00
2012-1-30 10:15:00
2012-3-30 10:15:00
2012-4-30 10:15:00
2012-5-30 10:15:00
2012-6-30 10:15:00
2012-7-30 10:15:00
2012-8-30 10:15:00
2012-9-30 10:15:00
2012-10-30 10:15:00
2012-11-30 10:15:00
2012-12-30 10:15:00
2013-1-30 10:15:00
4

3 回答 3

0

尝试以下方法：

// starting variables
$startDate = "2011-11-30";
$time = '10:15:00';
$numberOfTimesToRepeat = 10;

// Set our counts to 0
$count = 0;
$datesFound = 0;

// parse date
list($startYear,$startMonth,$startDay) = explode('-',$startDate);

// Create an array
while ($datesFound < $numberOfTimesToRepeat) {

    // Calculate number of months to add
    $monthsToAdd = fmod($count,12);

    // Calculate new month number
    $newMonth = (($startMonth + $monthsToAdd) > 12) ? ($startMonth + $monthsToAdd - 12) : ($startMonth + $monthsToAdd);

    // Add the leading 0 if necessary   
    if ($newMonth < 10 && strlen($newMonth) < 2) $newMonth = '0'.$newMonth;

    // Calculate number of months to add
    $yearsToAdd = floor(($count/12));

    $newYear = $startYear + $yearsToAdd;

    if (checkdate($newMonth,$startDay,$newYear)) {
        $dates[] = $newYear.'-'.$newMonth.'-'.$startDay.' '.$time;
        $datesFound++;
    }

    // increase our count either way
    $count++;

}



// Show the dates
foreach ($dates as $date) {
    echo $date.'<br />';
}
于 2011-11-07T19:17:22.107 回答
0

你打电话时

 $start_date = date('Y-m-d G:i:s',(strtotime($start_date) + ($repeat_timing)));

它增加了 1 个月的日期，但它也补偿了 repeat_timing 变量。您将 2678400 秒添加到 2011 年 1 月 30 日的日期，大约相当于 2011 年 3 月 1 日。

您最好将月、日和年与日期变量分开并手动进行计算。这将防止 DATE 更改您的时间范围。

于 2011-11-07T07:56:56.857 回答
0

这是一个简短的、值得信赖的函数，它与有效的日期时间戳相呼应：在线演示

function getValidDateTimes($date,$iterations){
    if(preg_match("/(\d{4})-(\d{1,2})-(\d{2}) (.*)/",$date,$n)){ // capture datetime bits
        list(,$Y,$n,$d,$time)=$n;       // declare bits as variables for readability
        for(++$n,$x=0; $x<$iterations; ++$x,++$n){  // start with month after $start_date
            $n=($n>12?"1":$n);              // reset to 1 when month exceeds 12
            $date="$Y-$n-$d";               // build literal new date
            if($date==date("Y-n-d",strtotime($date))){  // built date versus assumed date
                echo "$date $time<br>";   // store valid date with concatenated time
            }
        }
    }
}

$start_date="2011-11-30 10:15:00";
$iterations=15;

getValidDateTimes($start_date,$iterations);

输出（根据需要/预期）：

2011-12-30 10:15:00
2011-1-30 10:15:00
2011-3-30 10:15:00
2011-4-30 10:15:00
2011-5-30 10:15:00
2011-6-30 10:15:00
2011-7-30 10:15:00
2011-8-30 10:15:00
2011-9-30 10:15:00
2011-10-30 10:15:00
2011-11-30 10:15:00
2011-12-30 10:15:00
2011-1-30 10:15:00
于 2017-03-23T12:17:24.343 回答