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Is there a way that I can access the other sim in my android? I have an android Cherry Mobile Orbit which is a dual sim android phone. I want to develop an SMS application for my phone, but only the 1st sim will be access. I want to access the other sim, so that when i press enter to send the message, there will be a prompt, that which sim the message will be sent. I know that it's propreitary, but the phone manufacturer has no feedback about it. Is there any other way? tweaking or something?

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4 回答 4

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我认为你可以使用 dex2jar 或 apktool 来反转那些在双卡设备上运行的应用程序，一旦你找到相关的“服务管理器”，“电话管理器”，一些接口存根，或者像“Gemini”这样的关键词，你就可以使用Java Reflection，反射这个类的所有方法。然后你就可以实现这个目标。

于 2013-11-24T06:28:16.533 回答
1

此方法可用于从 2 个 SIM 中选择一个 SIM！

//above Android API 22
if (Build.VERSION.SDK_INT > 22) {
    //for dual sim mobile
    SubscriptionManager localSubscriptionManager = SubscriptionManager.from(this);

    if (localSubscriptionManager.getActiveSubscriptionInfoCount() > 1) {
     //if there are two sims in dual sim mobile
        List localList = localSubscriptionManager.getActiveSubscriptionInfoList();
        SubscriptionInfo simInfo = (SubscriptionInfo) localList.get(0);
        SubscriptionInfo simInfo1 = (SubscriptionInfo) localList.get(1);

        final String sim1 = simInfo.getDisplayName().toString();
        final String sim2 = simInfo1.getDisplayName().toString();

    }else{
     //if there is 1 sim in dual sim mobile
        TelephonyManager tManager = (TelephonyManager) getBaseContext()
                .getSystemService(Context.TELEPHONY_SERVICE);

        String sim1 = tManager.getNetworkOperatorName();

    }

}else{
    //below android API 22
            TelephonyManager tManager = (TelephonyManager) getBaseContext()
                    .getSystemService(Context.TELEPHONY_SERVICE);

            String sim1 = tManager.getNetworkOperatorName();
}

然后发送短信，您可以使用以下方法

    public static boolean sendSMS(Context context, String smsText) {
    SmsManager smsMan = SmsManager.getDefault();

    SharedPreferences prefs = context.getSharedPreferences("uinfo", MODE_PRIVATE);
    String sim = prefs.getString("sim", "No name defined");
    String simName = prefs.getString("simName", "No name defined");
    String toNum = "";

    try {

        if (Build.VERSION.SDK_INT > 22) {

            SubscriptionManager localSubscriptionManager = SubscriptionManager.from(context);
            if (localSubscriptionManager.getActiveSubscriptionInfoCount() > 1) {

                int simID  = Integer.parseInt(sim);

                List localList = localSubscriptionManager.getActiveSubscriptionInfoList();
                SubscriptionInfo simInfo = (SubscriptionInfo) localList.get(simID);
                ArrayList<String> parts = smsMan.divideMessage(smsText);
                SmsManager.getSmsManagerForSubscriptionId(simInfo.getSubscriptionId()).sendMultipartTextMessage(toNum, null, parts, null, null);
            }else{
                ArrayList<String> parts = smsMan.divideMessage(smsText);
                smsMan.sendMultipartTextMessage(toNum, null, parts, null, null);
            }
            return true;
        }else{
            ArrayList<String> parts = smsMan.divideMessage(smsText);
            smsMan.sendMultipartTextMessage(toNum, null, parts, null, null);
        }
    } catch (Exception e) {

    }
    return false;
}
于 2020-11-26T21:25:29.483 回答
0

官方目前没有支持此功能的 API，您必须联系设备制造商。

于 2011-11-05T07:46:22.990 回答
0

假设您正在为自己的手机开发应用程序，并且您愿意费力找出sim_id分配给每张 SIM 卡的 ID ( )（可能通过检查手机的日志输出，搜索sim_id，这就是我做了），您可以使用以下代码设置短信发送的默认 SIM 卡：

int simId = <place desired SIM ID here>;
Intent simIntent = new Intent("android.intent.action.SMS_DEFAULT_SIM");
simIntent.putExtra("simid", simId);
sendBroadcast(simIntent);

结合其他一些 UI 提示内容（用于实际“选择”首选 SIM 卡），这应该可以解决问题。

我完全不确定这种方法是否适合您（尽管代码看起来很“标准”）；我在我的 Mlais MX28（带有定制的 ROM）上反复试验发现了这一点。但我想它仍然值得一试。:)

更新： 奇怪的是，在对我正在开发的应用程序进行了几次更新后，该解决方案意外停止工作。但我遇到了另一种方式（这似乎更有希望）。（我相信这也可以扩展到其他 SIM 选择场景，因为设置缓存包含带有names gprs_connection_sim_setting、voice_call_sim_setting等video_call_sim_setting的条目。）

ContentValues val = new ContentValues();
val.put("value", "here goes the preferred SIM ID");
getContentResolver().update(Uri.parse("content://settings/system"), val, "name='sms_sim_setting'", null);

（不幸的是，这需要android.permission.WRITE_SETTINGS许可。）

于 2015-04-13T16:10:27.820 回答