7

我正在尝试选择单元格值以用户按下的相同 keychar 开头的第一行。这就是给我带来麻烦的部分。

这是我处理事件的方式（使用工作解决方案更新）：

private void dataGridView1_KeyPress(object sender, KeyPressEventArgs e)
{
    if (Char.IsLetter(e.KeyChar))
    {
        for (int i = 0; i < (dataGridView1.Rows.Count); i++)
        {
            if (dataGridView1.Rows[i].Cells["Name"].Value.ToString().StartsWith(e.KeyChar.ToString(), true, CultureInfo.InvariantCulture))
            {
                dataGridView1.Rows[i].Cells[0].Selected = true;
                return; // stop looping
            }
        }
    }
}

我敢肯定，我忽略了一些简单的事情，但是对于我的生活，我无法弄清楚它是什么。

编辑

更新了代码并应用了解决方案

4

5 回答 5

4

可能是一个案例问题，单元格中的值[“名称”]是否以大写字母开头？尝试在两者上使用 ToUpper 或 ToLower；或者您可以尝试 StartsWith(e.KeyChar, true) 来忽略大小写。如果您尝试选择行，则需要执行 dataGridView1.Rows[i].Selected = true

于 2009-04-28T13:41:49.053 回答
2 
if (Char.IsLetterOrDigit(e.KeyChar))
{
    foreach (DataGridViewRow dgvRow in myDgv.Rows)
    {
        if (dgvRow.Cells["ColumnName"].FormattedValue
            .ToString().StartsWith(e.KeyChar.ToString(), true, CultureInfo.InvariantCulture))
        {
            dgvRow.Selected = true;
            break;
        }
    }
}

如果 DGV 设置为允许多选，那么您显然希望取消选择任何现有的选择。

于 2009-04-28T13:53:55.033 回答
2

如果有多个名称以同一个字母开头的实例，则原始问题中的编辑答案不支持跳转到下一个字母。这是支持此功能的已编辑答案：

private void dataGridView1_KeyPress(object sender, KeyPressEventArgs e)
{
    if (Char.IsLetter(e.KeyChar))
    {
        int index = 0;
        // This works only if dataGridView1's SelectionMode property is set to FullRowSelect
        if (dataGridView1.SelectedRows.Count > 0 )
        {
            index = dataGridView1.SelectedRows[0].Index + 1
        }
        for (int i = index; i < (dataGridView1.Rows.Count + index); i++)
        {
            if (dataGridView1.Rows[i % dataGridView1.Rows.Count].Cells["Name"].Value.ToString().StartsWith(e.KeyChar.ToString(), true, CultureInfo.InvariantCulture))
            {
                foreach (var row in dataGridView1.Rows.Cast<DataGridViewRow>().Where(t => t.Selected))
                {
                    row.Selected = false;
                }
                dataGridView1.Rows[i % dataGridView1.Rows.Count].Cells[0].Selected = true;
                return; // stop looping
            }
        }
    }
}
于 2014-10-23T07:14:01.120 回答
1

这是一个 VS2008 VB.NET DataGridView 扩展，旨在完成您正在做的事情，但使用 TextBox 来搜索信息（设计时不考虑大小写，但可以轻松添加）。这个扩展有效，所以也许有些东西可能会有所帮助。我确实注意到您的代码使用 select 选择了一行，而我使用的是 CurrentCell。

    <Runtime.CompilerServices.Extension()> _
Public Function PartSeek(ByVal GridView As DataGridView, ByVal ColumnName As String, ByVal Value As String, ByVal Part As Boolean) As Boolean
    Dim Located As Boolean = False

    If GridView.Columns.Contains(ColumnName) Then
        Dim SingleRow As DataGridViewRow
        If Part Then
            SingleRow = (From Rows In GridView.Rows.Cast(Of DataGridViewRow)() _
                         Where Rows.Cells(ColumnName).Value.ToString().Contains(Value)).FirstOrDefault
        Else
            SingleRow = (From Rows In GridView.Rows.Cast(Of DataGridViewRow)() _
                         Where Rows.Cells(ColumnName).Value.ToString() = Value).FirstOrDefault
        End If
        If Not IsNothing(SingleRow) Then
            If GridView.CurrentCell.RowIndex <> SingleRow.Index Then
                GridView.CurrentCell = GridView(0, SingleRow.Index)
            End If
            DirectCast(GridView.Parent, Form).ActiveControl = GridView
            Located = True
        End If
        Return Located
    Else
        Throw New Exception("Column '" & ColumnName & "' not contained in this DataGridView")
    End If

End Function
于 2009-04-29T21:50:38.933 回答
1

我在 VB.NET 中使用它。您可以使用http://www.developerfusion.com/tools/转换为 C Sharp。

我写了一个方法来选择输入的行字母。该函数在 DataGridView 的 KeysPress 事件处理程序中调用。

方法：

'user types letter in dgv, method will select the column starting with that letter if it exists or else next letter existing in dgv
Public Shared Sub GoToLetterTypedInDataGridView(ByVal dgv As DataGridView, ByVal columnName As String, ByVal columnPosition As Integer, ByVal letterTyped As Char)
    Try
        Dim dt As DataTable = dgv.DataSource
        Dim letter As Char = letterTyped
        Dim dv As DataView = New DataView(dt)
        Dim hasCount As Boolean = False

        While (Not hasCount)
            dv.Sort = columnName
            dv.RowFilter = columnName & " like '" & letter & "%'"
            If dv.Count > 0 Then
                hasCount = True
                Dim x As String = dv(0)(columnPosition).ToString()
                Dim bs As New BindingSource
                bs.DataSource = dt
                dgv.BindingContext(bs).Position = bs.Find(columnName, x)
                dgv.CurrentCell = dgv(0, bs.Position)
            Else
                If letter = "z" Then
                    letter = "a"
                ElseIf letter = "Z" Then
                    letter = "A"
                Else : letter = Chr(Asc(letter) + 1)
                End If
            End If
        End While
    Catch ex As Exception
        Dim stackframe As New Diagnostics.StackFrame(1)
        Throw New Exception("An error occurred in routine, '" & stackframe.GetMethod.ReflectedType.Name & "." & System.Reflection.MethodInfo.GetCurrentMethod.Name & "'." & Environment.NewLine & "  Message was: '" & ex.Message & "'")
    End Try
End Sub

然后调用：

Private Sub dgvNew_KeyPress(sender As Object, e As System.Windows.Forms.KeyPressEventArgs) Handles dgvNew.KeyPress
Try
    If dgvNew.RowCount > 0 Then
        GoToLetterTypedInDataGridView(dgvNew, "columnName", 0, e.KeyChar)
    End If
Catch ex As Exception
    Dim stackframe As New Diagnostics.StackFrame(1)
    Throw New Exception("An error occurred in routine, '" & stackframe.GetMethod.ReflectedType.Name & "." & System.Reflection.MethodInfo.GetCurrentMethod.Name & "'." & Environment.NewLine & "  Message was: '" & ex.Message & "'")
End Try

结束子

希望这可以帮助！琥珀色

于 2012-11-09T21:04:50.167 回答