php - 通过 CLI 运行 CodeIgniter 脚本 - 缺少 CI 超级对象方法

Question

我有一个 CodeIgniter 项目，我想通过 CLI 调用我的控制器方法之一，但是附加到 CI 超级对象的正常属性和方法似乎丢失了？

例如，运行以下在正常 http 请求期间运行良好的脚本会产生错误：

class Worker extends MY_Controller {

    public function __construct() {
        if(php_sapi_name() !== 'cli') {
            show_404();
        }
    }

    public function test(){

        $this->load->library('some_library');

    }
}

这是通过 CLI 返回的错误

  <div style="border:1px solid #990000;padding-left:20px;margin:0 0 10px 0;">

<h4>A PHP Error was encountered</h4>

<p>Severity: Notice</p>
<p>Message:  Trying to get property of non-object</p>
<p>Filename: controllers/worker.php</p>
<p>Line Number: 21</p>

</div>PHP Fatal error:  Call to a member function library() on a non-object in /Users/casey/Documents/workspaces/vibecompass_live/application/controllers/worker.php on line 21

Fatal error: Call to a member function library() on a non-object in /Users/casey/Documents/workspaces/vibecompass_live/application/controllers/worker.php on line 21

我这样调用脚本： $ php index.php worker test

编辑

此外，此脚本：

class Worker extends MY_Controller {

    public function __construct() {
        if(php_sapi_name() !== 'cli') {
            show_404();
        }
    }

    public function test(){

        $CI =& get_instance();
        var_dump($CI); die();

        $this->load->library('some_library');

    }
}

回报：NULL

Answer 1

看起来您还没有初始化父类，在您的控制器构造函数中，也调用了父构造函数：

class Worker extends MY_Controller {

    public function __construct() {
        parent::__construct();
        if(php_sapi_name() !== 'cli') {
            show_404();
        }
    }