shell - Heads and Tails - 试图获取每个文件的第一行和最后十行

Question

我有一个输出文件目录，我想按顺序显示每个文件的第一行和每个文件的最后十行。

我已经完成了部分命令：

ls output/*Response | sort -t_ --key=2 -g | xargs tail | less

这给了我这样的东西：

==> output/Acdb_18_Response <==
150707,"SOVO","Other","","","","","","160x600",0,0,1432,0,0,1432
167493,"Asper","Other","","","","","","160x600",143200,0,0,1432,0,0
269774,"AIKA","Other","","","","","","160x600",0,1432,0,0,1432,0
342275,"Lorrum","Other","","","","","","160x600",0,0,1432,0,0,1432
347954,"Game","Other","","","","","","160x600",0,1432,0,0,1432,0
418858,"Technologies","Other","","","","","","160x600",0,1432,0,0,1432,0
24576,"Media ","Other","","","","","","300x600",0,0,1432,0,0,1432
23351," Plus","Other","","","","","","425x600",0,4296,0,0,4296,0
#rowcount=79

这很好，但我想包括第一行来获取标题。我尝试将输出端输出到头部，但到目前为止我还无法弄清楚如何安排管道。

有什么建议么？

Answer 1

ls output/*Response | sort -t_ --key=2 -g \
    | xargs -I {} sh -c 'head -1 {}; tail {}' | less

Answer 2

您还可以尝试以下方法：

ls output/*Response | sort -t_ --key=2 -g | ((head -n 1) && (tail -n 10)) | less